This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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5(ii)(a) Step 1: Write the unbalanced equation. Fe + CuSO_4 FeSO_4 + Cu Step 2: Check atoms on both sides. Left: Fe = 1, Cu = 1, S = 1, O = 4 Right: Fe = 1, Cu = 1, S = 1, O = 4 Balanced as is. Balanced equation: Fe + CuSO_4 FeSO_4 + Cu Fe + CuSO_4 FeSO_4 + Cu 5(ii)(b) Step 1: Write the unbalanced equation. MnO_2 + HCl MnCl_2 + H_2O + Cl_2 Step 2: Balance Mn: coefficient 1 on both (already). MnO_2 + HCl MnCl_2 + H_2O + Cl_2 Step 3: Balance O: 2 on left, so 2 H₂O on right. MnO_2 + HCl MnCl_2 + 2H_2O + Cl_2 Step 4: Balance H: 4 on right (from 2H₂O), so 4 HCl on left. MnO_2 + 4HCl MnCl_2 + 2H_2O + Cl_2 Step 5: Balance Cl: 4 on left, 2 from MnCl₂ + 2 from Cl₂ = 4 on right. Balanced equation: MnO_2 + 4HCl MnCl_2 + Cl_2 + 2H_2O MnO_2 + 4HCl MnCl_2 + Cl_2 + 2H_2O 6(i) Step 1: Thermal decomposition of lead nitrate. Unbalanced: Pb(NO_3)_2 PbO + NO_2 + O_2 Step 2: Balance Pb: 2 on left, so 2 PbO on right. 2Pb(NO_3)_2 2PbO + NO_2 + O_2 Step 3: N: 4 on left, 4 NO₂ on right. 2Pb(NO_3)_2 2PbO + 4NO_2 + O_2 Step 4: O: left 12, right 2(1) + 4(2) + 2(1)/2 wait, O₂ is 2O. Right: 2PbO=2O, 4NO₂=8O, O₂=2O total 12O. Balanced. IUPAC names of products: lead(II) oxide, nitrogen dioxide, dioxygen Reaction: 2Pb(NO_3)_2 ->[heat] 2PbO + 4NO_2 + O_2 2Pb(NO_3)_2 ->[Δ] 2PbO + 4NO_2 + O_2 6(ii)(a) Step 1: Identify structure: CH₃-CH₂-CHO (three carbons, aldehyde). IUPAC name: propanal propanal