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Write and balance the chemical equation for the thermal decomposition of lithium nitrate.

Chemistry

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Step-by-step solution

3 steps
  1. Identify the decomposition products of lithium nitrate.

    Lithium nitrate, unlike other alkali metal nitrates, decomposes upon heating to form lithium oxide, nitrogen dioxide gas, and oxygen gas. This is due to lithium's small size and high polarizing power, which makes its decomposition similar to that of Group 2 nitrates.

  2. Write the unbalanced chemical equation.

    LiNO3(s)→ΔLi2O(s)+NO2(g)+O2(g)LiNO_3(s) \xrightarrow{\Delta} Li_2O(s) + NO_2(g) + O_2(g)
  3. Balance the chemical equation.

    To balance the lithium atoms, we need 2 moles of LiNO3_3 to produce 1 mole of Li2_2O.

    2LiNO3(s)→ΔLi2O(s)+2NO2(g)+O2(g)2LiNO_3(s) \xrightarrow{\Delta} Li_2O(s) + 2NO_2(g) + O_2(g)

    Now, let's check the oxygen atoms:
    Reactants: 2×3=62 \times 3 = 6 oxygen atoms.
    Products: 1 (from Li2_2O) +(2×2)+ (2 \times 2) (from NO2_2) +2+ 2 (from O2_2) =1+4+2=7= 1 + 4 + 2 = 7 oxygen atoms.
    The oxygen atoms are not balanced. We need to adjust the coefficients.
    Let's try starting with 4 moles of LiNO3_3.

    4LiNO3(s)→Δ2Li2O(s)+4NO2(g)+O2(g)4LiNO_3(s) \xrightarrow{\Delta} 2Li_2O(s) + 4NO_2(g) + O_2(g)

    Check the balance:
    Lithium (Li): Reactants = 4, Products = 2×2=42 \times 2 = 4. (Balanced)
    Nitrogen (N): Reactants = 4, Products = 4×1=44 \times 1 = 4. (Balanced)
    Oxygen (O): Reactants = 4×3=124 \times 3 = 12. Products = 2 (from Li2_2O) +(4×2)+ (4 \times 2) (from NO2_2) +2+ 2 (from O2_2) =2+8+2=12= 2 + 8 + 2 = 12. (Balanced)

    The balanced chemical equation for the thermal decomposition of lithium nitrate is:

    4LiNO3(s)→Δ2Li2O(s)+4NO2(g)+O2(g)\boxed{4LiNO_3(s) \xrightarrow{\Delta} 2Li_2O(s) + 4NO_2(g) + O_2(g)}
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