This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
..._2SO_3 (s) + H_2SO_4 (aq) Na_2SO_4 (aq) + H_2O (l) + SO_2 (g) Both carbon dioxide (CO_2) and sulfur dioxide (SO_2) gases are evolved. CO_2 is odorless, while SO_2 has a pungent, suffocating smell. Step 2: To identify SO_3^2- (sulfite radical), pass the evolved gas mixture through an acidified potassium dichromate (K_2Cr_2O_7) solution. Sulfur dioxide (SO_2) will reduce the orange dichromate solution to a green solution due to the formation of Cr^3+ ions. Carbon dioxide (CO_2) does not react with acidified potassium dichromate. Cr_2O_7^2- (aq) + 3SO_2 (g) + 2H^+ (aq) 2Cr^3+ (aq) + 3SO_4^2- (aq) + H_2O (l) The change from orange to green confirms the presence of the sulfite radical (SO_3^2-). Step 3: To identify CO_3^2- (carbonate radical), pass the gas that emerges from the potassium dichromate solution (which now contains only CO_2, as SO_2 has been removed) through limewater (Ca(OH)_2 solution). If CO_2 is present, the limewater will turn milky due to the formation of insoluble calcium carbonate. Ca(OH)_2 (aq) + CO_2 (g) CaCO_3 (s) + H_2O (l) The milky precipitate confirms the presence of the carbonate radical (CO_3^2-). Last free one today — make it count tomorrow, or type /upgrade for unlimited.