This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Step 1: Identify the symbols and their valencies. Aluminium (Al) has a valency of 3. Oxygen (O) has a valency of 2. Step 2: Apply the cross-over method. The valency of Aluminium becomes the subscript for Oxygen. The valency of Oxygen becomes the subscript for Aluminium. Step 3: Write the chemical formula. Al_2O_3 The chemical formula for Aluminium Oxide is Al_2O_3. b) Magnesium Chloride Step 1: Identify the symbols and their valencies. Magnesium (Mg) has a valency of 2. Chlorine (Cl) has a valency of 1. Step 2: Apply the cross-over method. The valency of Magnesium becomes the subscript for Chlorine. The valency of Chlorine becomes the subscript for Magnesium. Step 3: Write the chemical formula. MgCl_2 The chemical formula for Magnesium Chloride is MgCl_2. a) Name the specific radical present in this compound. The compound is Ca(OH)_2. The radical present is OH. This radical is known as the hydroxide radical. The specific radical present is Hydroxide. b) Determine the total number of atoms present in Ca(OH)_2. The formula is Ca(OH)_2. • Number of Calcium (Ca) atoms = 1 • The subscript 2 outside the parenthesis means there are two OH groups. • Number of Oxygen (O) atoms = 1 × 2 = 2 • Number of Hydrogen (H) atoms = 1 × 2 = 2 Total number of atoms = (Ca atoms) + (O atoms) + (H atoms) Total number of atoms = 1 + 2 + 2 = 5 The total number of atoms present in Ca(OH)_2 is 5. Send me the next one 📸