This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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here are the solutions for the Mole Concept Calculations: 1. Calculate the number of moles in 44 g of CO₂. Step 1: Determine the molar mass of CO₂. The atomic mass of Carbon (C) is approximately 12.01 g/mol. The atomic mass of Oxygen (O) is approximately 16.00 g/mol. Molar mass of CO_2 = 12.01 g/mol + (2 × 16.00 g/mol) = 12.01 g/mol + 32.00 g/mol = 44.01 g/mol Step 2: Calculate the number of moles using the formula: moles = massmolar mass. Moles of CO_2 = 44 g44.01 g/mol ≈ 0.9998 mol Rounding to a reasonable number of significant figures: The number of moles in 44 g of CO₂ is 1.00 mol. 2. Determine the mass of 0.5 mole of H₂SO₄. Step 1: Determine the molar mass of H₂SO₄. The atomic mass of Hydrogen (H) is approximately 1.01 g/mol. The atomic mass of Sulfur (S) is approximately 32.07 g/mol. The atomic mass of Oxygen (O) is approximately 16.00 g/mol. Molar mass of H_2SO_4 = (2 × 1.01 g/mol) + 32.07 g/mol + (4 × 16.00 g/mol) = 2.02 g/mol + 32.07 g/mol + 64.00 g/mol = 98.09 g/mol Step 2: Calculate the mass using the formula: mass = moles × molar mass. Mass of H_2SO_4 = 0.5 mol × 98.09 g/mol = 49.045 g The mass of 0.5 mole of H₂SO₄ is 49.05 g. 3. Calculate the number of molecules in 2 moles of oxygen. Step 1: Recall Avogadro's number. Avogadro's number is 6.022 × 10^23 molecules/mol. Step 2: Calculate the number of molecules using the formula: number of molecules = moles × Avogadro's number. Oxygen gas exists as diatomic molecules, O₂. Number of O_2 molecules = 2 mol × (6.022 × 10^23 molecules/mol) = 1.2044 × 10^24 molecules The number of molecules in 2 moles of oxygen is 1.204 × 10^24 molecules. 4. What volume will 0.25 mole of a gas occupy at s.t.p.? Step 1: Recall the molar volume of a gas at s.t.p. At Standard Temperature and Pressure (s.t.p.), 1 mole of any ideal gas occupies 22.4 dm^3 (or 22.4 L). Step 2: Calculate the volume using the formula: volume = moles × molar volume at s.t.p.. Volume = 0.25 mol × 22.4 dm^3/mol = 5.6 dm^3 The volume occupied by 0.25 mole of a gas at s.t.p. is 5.6 dm^3. Got more? Send 'em!