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Determine the concentration of the acid in mol/dm³.

Chemistry

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It looks like you've sent the same question again, Miriam! I'll re-provide the solution for part (d) from the previous problem.

d) Determine the concentration of the acid in mol/dm³.
Given:
Concentration of Na2CO3\text{Na}_2\text{CO}_3 (CBC_B) = 0.1 M
Volume of Na2CO3\text{Na}_2\text{CO}_3 (VBV_B) = 25 cm³ = 0.025 dm³
Volume of H2SO4\text{H}_2\text{SO}_4 (VAV_A) = 20 cm³ = 0.020 dm³

d) (i) Determine the concentration of the acid in mol/dm³.

  1. Write the balanced chemical equation for the reaction.

    H2SO4(aq)+Na2CO3(aq)⟶Na2SO4(aq)+CO2(g)+H2O(l)\text{H}_2\text{SO}_4(\text{aq}) + \text{Na}_2\text{CO}_3(\text{aq}) \longrightarrow \text{Na}_2\text{SO}_4(\text{aq}) + \text{CO}_2(\text{g}) + \text{H}_2\text{O}(\text{l})

    From the balanced equation, the mole ratio of H2SO4:Na2CO3\text{H}_2\text{SO}_4 : \text{Na}_2\text{CO}_3 is 1:11:1.

  2. Calculate the moles of Na2CO3\text{Na}_2\text{CO}_3 used.

    Moles of Na2CO3=CB×VB\text{Moles of Na}_2\text{CO}_3 = C_B \times V_B Moles of Na2CO3=0.1 mol/dm3×0.025 dm3=0.0025 mol\text{Moles of Na}_2\text{CO}_3 = 0.1 \text{ mol/dm}^3 \times 0.025 \text{ dm}^3 = 0.0025 \text{ mol}
  3. Determine the moles of H2SO4\text{H}_2\text{SO}_4 reacted.

    Since the mole ratio is 1:11:1,

    Moles of H2SO4=Moles of Na2CO3=0.0025 mol\text{Moles of H}_2\text{SO}_4 = \text{Moles of Na}_2\text{CO}_3 = 0.0025 \text{ mol}
  4. Calculate the concentration of H2SO4\text{H}_2\text{SO}_4.

    Concentration of H2SO4=Moles of H2SO4Volume of H2SO4(indm3)\text{Concentration of H}_2\text{SO}_4 = \frac{\text{Moles of H}_2\text{SO}_4}{\text{Volume of H}_2\text{SO}_4 (in dm}^3\text{)} Concentration of H2SO4=0.0025 mol0.020 dm3\text{Concentration of H}_2\text{SO}_4 = \frac{0.0025 \text{ mol}}{0.020 \text{ dm}^3} Concentration of H2SO4=0.125 mol/dm3\text{Concentration of H}_2\text{SO}_4 = \boxed{0.125 \text{ mol/dm}^3}

    d) (ii) The reaction is:

    H2SO4+Na2CO3⟶Na2SO4+CO2+H2O\text{H}_2\text{SO}_4 + \text{Na}_2\text{CO}_3 \longrightarrow \text{Na}_2\text{SO}_4 + \text{CO}_2 + \text{H}_2\text{O}
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