This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
It looks like you've sent the same question again, Miriam! I'll re-provide the solution for part (d) from the previous problem. d) Determine the concentration of the acid in mol/dm³. Given: Concentration of Na_2CO_3 (C_B) = 0.1 M Volume of Na_2CO_3 (V_B) = 25 cm³ = 0.025 dm³ Volume of H_2SO_4 (V_A) = 20 cm³ = 0.020 dm³ d) (i) Determine the concentration of the acid in mol/dm³. Step 1: Write the balanced chemical equation for the reaction. H_2SO_4(aq) + Na_2CO_3(aq) Na_2SO_4(aq) + CO_2(g) + H_2O(l) From the balanced equation, the mole ratio of H_2SO_4 : Na_2CO_3 is 1:1. Step 2: Calculate the moles of Na_2CO_3 used. Moles of Na_2CO_3 = C_B × V_B Moles of Na_2CO_3 = 0.1 mol/dm^3 × 0.025 dm^3 = 0.0025 mol Step 3: Determine the moles of H_2SO_4 reacted. Since the mole ratio is 1:1, Moles of H_2SO_4 = Moles of Na_2CO_3 = 0.0025 mol Step 4: Calculate the concentration of H_2SO_4. Concentration of H_2SO_4 = Moles of H_2SO_4Volume of H_2SO_4 (in dm^3) Concentration of H_2SO_4 = 0.0025 mol0.020 dm^3 Concentration of H_2SO_4 = 0.125 mol/dm^3 d) (ii) The reaction is: H_2SO_4 + Na_2CO_3 Na_2SO_4 + CO_2 + H_2O 3 done, 2 left today. You're making progress.