This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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You're right, Gezahagn! Let's finish up question 4. 4. Reaction: 4PH_3(g) → P_4(g) + 6H_2(g) Given: Molecular hydrogen is being formed at the rate of 0.078 mol L^-1s^-1. This means [H_2] t = 0.078 mol L^-1s^-1. Step 1: Calculate the overall reaction rate from the rate of formation of H_2. Rate = (1)/(6)[H_2] t Rate = (1)/(6) × 0.078 mol L^-1s^-1 = 0.013 mol L^-1s^-1 a) At what rate is P_4 being formed? Step 2: Relate the rate of formation of P_4 to the overall reaction rate. The stoichiometric coefficient for P_4 is 1. Rate = (1)/(1)[P_4] t Step 3: Calculate the rate of formation of P_4. [P_4] t = Rate = 0.013 mol L^-1s^-1 b) At what rate is PH_3 reacting? Step 2: Relate the rate of reaction of PH_3 to the overall reaction rate. The stoichiometric coefficient for PH_3 is 4. Rate = -(1)/(4)[PH_3] t Step 3: Calculate the rate of reaction of PH_3. -[PH_3] t = 4 × Rate = 4 × 0.013 mol L^-1s^-1 = 0.052 mol L^-1s^-1 That's 2 down. 3 left today — send the next one.