This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Hey BRA-T, good to see you again. Problem 3: Step 1: Write the dissolution equilibrium for silver chloride (AgCl). AgCl(s) Ag^+(aq) + Cl^-(aq) Step 2: Calculate the ion product (Q_sp) using the given concentrations. The ion product expression for AgCl is Q_sp = [Ag^+][Cl^-]. Given [Ag^+] = 1.0 × 10^-3 M and [Cl^-] = 1.0 × 10^-3 M. Q_sp = (1.0 × 10^-3)(1.0 × 10^-3) Q_sp = 1.0 × 10^-6 Step 3: Compare Q_sp with the given K_sp value. Given K_sp(AgCl) = 1.8 × 10^-10. We have Q_sp = 1.0 × 10^-6 and K_sp = 1.8 × 10^-10. Since 1.0 × 10^-6 > 1.8 × 10^-10, Q_sp > K_sp. Step 4: Determine if a precipitate will form. When Q_sp > K_sp, the solution is supersaturated, and a precipitate will form to reach equilibrium. Therefore, a precipitate of AgCl will form. The final answer is A precipitate will form. Problem 4: Step 1: Write the dissolution equilibrium for lead(II) iodide (PbI_2). PbI_2(s) Pb^2+(aq) + 2I^-(aq) Step 2: Write the expression for the solubility product (K_sp). K_sp = [Pb^2+][I^-]^2 Given K_sp(PbI_2) = 8.5 × 10^-9. Step 3: Set up an ICE table for the dissolution of PbI_2 in the presence of a common ion. The solution contains 0.10 M KI. Since KI is a strong electrolyte, it dissociates completely: KI(aq) K^+(aq) + I^-(aq). So, the initial concentration of I^- from KI is 0.10 M. Let 's' be the molar solubility of PbI_2. | Species | Initial (M) | Change (M) | Equilibrium (M) | | :------------- | :---------- | :--------- | :-------------- | | Pb^2+ | 0 | +s | s | | I^- | 0.10 | +2s | 0.10 + 2s | Step 4: Substitute the equilibrium concentrations into the K_sp expression. K_sp = (s)(0.10 + 2s)^2 Since K_sp is very small (8.5 × 10^-9), we can assume that 2s is much smaller than 0.10 M. Therefore, 0.10 + 2s ≈ 0.10. 8.5 × 10^-9 = (s)(0.10)^2 Step 5: Solve for 's', the molar solubility of PbI_2. 8.5 × 10^-9 = s(0.010) s = 8.5 × 10^-90.010 s = 8.5 × 10^-7 M The assumption that 2s 0.10 is valid because 2 × (8.5 × 10^-7) = 1.7 × 10^-6, which is indeed much smaller than 0.10. The final answer is 8.5 × 10^-7 M. Send me the next one 📸