Draw and name the structure of polymer formed from propene. Write an ionic equation for the reaction between sodium sulphate solution and lead (II) nitrate solution.

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Asked on April 20, 2026Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

Accepted Answer · 2026-04-20T10:23:53.441Z

You're on a roll — 15. (b) Draw and name the structure of polymer formed from propene. Propene is CH_2=CH-CH_3. During polymerization, the double bond breaks, and the monomers link together to form polypropene. The repeating unit of polypropene is: & CH_3 \\ & | \\ - & CH_2 & - & CH & - _n The name of the polymer is Polypropene. 16. (a) Write an ionic equation for the reaction between sodium sulphate solution and lead (II) nitrate solution. The reaction is between lead (II) nitrate (Pb(NO_3)_2) and sodium sulphate (Na_2SO_4) to form lead (II) sulphate (PbSO_4) precipitate and sodium nitrate (NaNO_3). Pb(NO_3)_2 (aq) + Na_2SO_4 (aq) PbSO_4 (s) + 2NaNO_3 (aq) The full ionic equation is: Pb^2+ (aq) + 2NO_3^- (aq) + 2Na^+ (aq) + SO_4^2- (aq) PbSO_4 (s) + 2Na^+ (aq) + 2NO_3^- (aq) The net ionic equation, removing spectator ions, is: Pb^2+ (aq) + SO_4^2- (aq) PbSO_4 (s) (b) Determine the mass of the lead salt formed in the reaction in (a) above. The lead salt formed is lead (II) sulphate (PbSO_4). The initial lead powder (0.63 g) is converted entirely into Pb^2+ ions, which then form PbSO_4. Step 1: Calculate the molar mass of lead (Pb). Given Pb = 207. Molar mass of Pb = 207 g/mol. Step 2: Calculate the moles of lead (Pb) from the initial sample. Moles of Pb = Mass of PbMolar mass of Pb = 0.63 g207 g/mol Step 3: Determine the moles of lead (II) sulphate (PbSO_4) formed. From the ionic equation, 1 mole of Pb^2+ produces 1 mole of PbSO_4. So, Moles of PbSO_4 = Moles of Pb = (0.63)/(207) mol. Step 4: Calculate the molar mass of lead (II) sulphate (PbSO_4). Given Pb = 207, S = 32, O = 16. Molar mass of PbSO_4 = 207 + 32 + (4 × 16) = 207 + 32 + 64 = 303 g/mol Step 5: Calculate the mass of lead (II) sulphate (PbSO_4) formed. Mass of PbSO_4 = Moles of PbSO_4 × Molar mass of PbSO_4 Mass of PbSO_4 = (0.63)/(207) mol × 303 g/mol Mass of PbSO_4 = (190.89)/(207) g Mass of PbSO_4 = 0.92217... g The mass of the lead salt formed is 0.922 g (to 3 significant figures). 17. For each of the following experiments, give the observations and the type of change that occurs (temporary physical or temporary chemical). | Experiment | Observation

Accepted Answer · 2026-04-20T10:23:53.441Z

You're on a roll — 15. (b) Draw and name the structure of polymer formed from propene. Propene is CH_2=CH-CH_3. During polymerization, the double bond breaks, and the monomers link together to form polypropene. The repeating unit of polypropene is: & CH_3 \\ & | \\ - & CH_2 & - & CH & - _n The name of the polymer is Polypropene. 16. (a) Write an ionic equation for the reaction between sodium sulphate solution and lead (II) nitrate solution. The reaction is between lead (II) nitrate (Pb(NO_3)_2) and sodium sulphate (Na_2SO_4) to form lead (II) sulphate (PbSO_4) precipitate and sodium nitrate (NaNO_3). Pb(NO_3)_2 (aq) + Na_2SO_4 (aq) PbSO_4 (s) + 2NaNO_3 (aq) The full ionic equation is: Pb^2+ (aq) + 2NO_3^- (aq) + 2Na^+ (aq) + SO_4^2- (aq) PbSO_4 (s) + 2Na^+ (aq) + 2NO_3^- (aq) The net ionic equation, removing spectator ions, is: Pb^2+ (aq) + SO_4^2- (aq) PbSO_4 (s) (b) Determine the mass of the lead salt formed in the reaction in (a) above. The lead salt formed is lead (II) sulphate (PbSO_4). The initial lead powder (0.63 g) is converted entirely into Pb^2+ ions, which then form PbSO_4. Step 1: Calculate the molar mass of lead (Pb). Given Pb = 207. Molar mass of Pb = 207 g/mol. Step 2: Calculate the moles of lead (Pb) from the initial sample. Moles of Pb = Mass of PbMolar mass of Pb = 0.63 g207 g/mol Step 3: Determine the moles of lead (II) sulphate (PbSO_4) formed. From the ionic equation, 1 mole of Pb^2+ produces 1 mole of PbSO_4. So, Moles of PbSO_4 = Moles of Pb = (0.63)/(207) mol. Step 4: Calculate the molar mass of lead (II) sulphate (PbSO_4). Given Pb = 207, S = 32, O = 16. Molar mass of PbSO_4 = 207 + 32 + (4 × 16) = 207 + 32 + 64 = 303 g/mol Step 5: Calculate the mass of lead (II) sulphate (PbSO_4) formed. Mass of PbSO_4 = Moles of PbSO_4 × Molar mass of PbSO_4 Mass of PbSO_4 = (0.63)/(207) mol × 303 g/mol Mass of PbSO_4 = (190.89)/(207) g Mass of PbSO_4 = 0.92217... g The mass of the lead salt formed is 0.922 g (to 3 significant figures). 17. For each of the following experiments, give the observations and the type of change that occurs (temporary physical or temporary chemical). | Experiment | Observation

Draw and name the structure of polymer formed from propene. Write an ionic equation for the reaction between sodium sulphate solution and lead (II) nitrate solution.

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Draw and name the structure of polymer formed from propene. Write an ionic equation for the reaction between sodium sulphate solution and lead (II) nitrate solution.

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