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Given the following rate data for F2(g) + 2ClO2(g) -> 2ClO2F(g), determine the order of reaction with respect to each reactant, the overall order of the reaction, write the rate equation for the reaction, and calculate the rate constant of the reaction.

Chemistry

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Here are the solutions based on the provided rate data:

The general rate law for the reaction F2(g)+2ClO2(g)⟶2FClO2(g)F_{2(g)} + 2ClO_{2(g)} \longrightarrow 2FClO_{2(g)} is Rate=k[F2]x[ClO2]yRate = k[F_2]^x[ClO_2]^y.

1. Determine the order of reaction with respect to each reactant.

  • Order with respect to F2F_2 (xx):
  1. Compare experiments where the concentration of ClO2ClO_2 is constant.

    Using Experiment 1 and Experiment 2, $[ClO_2]$ is constant at 0.15 M.
    $$
    \frac{Rate_1}{Rate_2} = \frac{k[F_2]_1^x[ClO_2]_1^y}{k[F_2]_2^x[ClO_2]_2^y}
    $$
    $$
    \frac{1.8 \times 10^{-5}}{1.8 \times 10^{-5}} = \left(\frac{0.105}{0.05}\right)^x \left(\frac{0.15}{0.15}\right)^y
    $$
    $$
    1 = (2.1)^x \cdot 1^y
    $$
    For this equation to be true, $x$ must be 0.  
    The order with respect to $F_2$ is $\boxed{0}$.
    
    • Order with respect to ClO2ClO_2 (yy):
  2. Compare experiments where the concentration of F2F_2 is constant.

    Using Experiment 3 and Experiment 4, $[F_2]$ is constant at 0.052 M.
    $$
    \frac{Rate_3}{Rate_4} = \frac{k[F_2]_3^x[ClO_2]_3^y}{k[F_2]_4^x[ClO_2]_4^y}
    $$
    $$
    \frac{7.1 \times 10^{-5}}{8.9 \times 10^{-6}} = \left(\frac{0.052}{0.052}\right)^x \left(\frac{0.30}{0.15}\right)^y
    $$
    $$
    7.9775 \approx (1)^x (2)^y
    $$
    $$
    7.9775 \approx 2^y
    $$
    Since $2^3 = 8$, $y$ is approximately 3.  
    The order with respect to $ClO_2$ is $\boxed{3}$.
    

    2. Determine the overall order of reaction.

  3. The overall order is the sum of the individual orders (x+yx+y).

    Overall order=0+3=3\text{Overall order} = 0 + 3 = \boxed{3}

    3. Write the rate equation for the reaction.

  4. Substitute the determined orders into the general rate law.

    Rate=k[F2]0[ClO2]3Rate = k[F_2]^0[ClO_2]^3

    Since [F2]0=1[F_2]^0 = 1:

    Rate=k[ClO2]3Rate = \boxed{k[ClO_2]^3}

    4. Calculate the rate constant of the reaction.

  5. Use the rate equation Rate=k[ClO2]3Rate = k[ClO_2]^3 and the data from any experiment to calculate kk.

    Note: There is an inconsistency in the provided data, as calculating kk from experiments 1 and 2 yields a different value than from experiments 3 and 4. We will use experiments 3 and 4, which were used to determine the order of ClO2ClO_2.

    • Using Experiment 3:

      7.1×10−5 M/s=k(0.30 M)37.1 \times 10^{-5} \text{ M/s} = k(0.30 \text{ M})^3 7.1×10−5 M/s=k(0.027 M3)7.1 \times 10^{-5} \text{ M/s} = k(0.027 \text{ M}^3) k=7.1×10−5 M/s0.027 M3=0.0026296 M−2s−1k = \frac{7.1 \times 10^{-5} \text{ M/s}}{0.027 \text{ M}^3} = 0.0026296 \text{ M}^{-2}\text{s}^{-1}
    • Using Experiment 4:

      8.9×10−6 M/s=k(0.15 M)38.9 \times 10^{-6} \text{ M/s} = k(0.15 \text{ M})^3 8.9×10−6 M/s=k(0.003375 M3)8.9 \times 10^{-6} \text{ M/s} = k(0.003375 \text{ M}^3) k=8.9×10−6 M/s0.003375 M3=0.0026370 M−2s−1k = \frac{8.9 \times 10^{-6} \text{ M/s}}{0.003375 \text{ M}^3} = 0.0026370 \text{ M}^{-2}\text{s}^{-1}

    Averaging the values from experiments 3 and 4:

    k=0.0026296+0.00263702 M−2s−1=0.0026333 M−2s−1k = \frac{0.0026296 + 0.0026370}{2} \text{ M}^{-2}\text{s}^{-1} = 0.0026333 \text{ M}^{-2}\text{s}^{-1}

    The rate constant is 0.00263 M−2s−1\boxed{0.00263 \text{ M}^{-2}\text{s}^{-1}}.

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