This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Step 1: Determine the degree of unsaturation (DoU) for the compound with molecular formula C_3H_4O. The formula for DoU is C + 1 - H2 - X2 + N2, where C is carbon, H is hydrogen, X is halogen, and N is nitrogen. For C_3H_4O: DoU = 3 + 1 - (4)/(2) - (0)/(2) + (0)/(2) = 4 - 2 = 2 A DoU of 2 indicates the presence of two double bonds, one triple bond, or one ring and one double bond. Step 2: Interpret the chemical properties. "Immediately decolorizes bromine water" indicates the presence of a carbon-carbon double bond (C=C) or a triple bond (C). This accounts for at least one degree of unsaturation. "Restore the colour to Schiff's reagent" indicates the presence of an aldehyde functional group (-CHO). An aldehyde group contains a carbon-oxygen double bond (C=O), which accounts for one degree of unsaturation. "Acid smelling distillate" refers to the pungent, acrid smell characteristic of small aldehydes. Step 3: Combine the functional groups with the molecular formula and DoU. Since the compound has an aldehyde group (C=O, 1 DoU) and a carbon-carbon double bond (C=C, 1 DoU), these two features together account for the total DoU of 2. With 3 carbon atoms, we can arrange these groups as follows: The aldehyde group is at one end of the carbon chain. The carbon-carbon double bond must be between the other two carbons. Step 4: Propose and verify the structure. The only possible arrangement for C_3H_4O containing both a C=C bond and an aldehyde (-CHO) group is prop-2-enal, also known as acrolein. Its structure is CH_2=CH-CHO. Let's check the formula: 3 carbons, 2+1+1 = 4 hydrogens, 1 oxygen. This matches C_3H_4O. The reaction of glycerol with a dehydrating agent like anhydrous magnesium sulfate is known to produce acrolein. The possible structure for the compound is: CH_2=CH-CHO Send me the next one 📸