Step 1: Identify the given compound. Let's analyze the structure provided in the image: $$ \begin{matrix} & \text{H} & \text{H} & \text{H} & \\ & | & | & | & \\ \text{H} & - & \text{C} & - & \text{C} & - & \text{C} & - & \text{C} & = & \text{O} \\ & | & | & | & | & & \\ & \text{H} & \text{H} & \text{C} & \text{H} & \\ & & & | & & \\ & & & \text{H} & \end{matrix} $$ This can be redrawn to clearly show the carbon chain and substituents: $$ \text{CH}_3 - \text{CH}(\text{CH}_3) - \text{CH}_2 - \text{CHO} $$ To name this compound: 1. Identify the longest carbon chain containing the aldehyde group ($\text{-CHO}$). This chain has 4 carbons. 2. Number the chain starting from the aldehyde carbon ($\text{C}_1$). $\text{C}_1$: $\text{CHO}$ $\text{C}_2$: $\text{CH}_2$ $\text{C}_3$: $\text{CH}$ (with a methyl group attached) $\text{C}_4$: $\text{CH}_3$ 3. Identify substituents: There is a methyl group ($\text{CH}_3$) on $\text{C}_3$. 4. The parent name is butanal (for a 4-carbon aldehyde). 5. The full IUPAC name is 3-methylbutanal. Step 2: Determine the type of alcohol that oxidizes to an aldehyde. • Primary alcohols ($\text{R-CH}_2\text{OH}$) oxidize to aldehydes ($\text{R-CHO}$). • Secondary alcohols ($\text{R}_2\text{CHOH}$) oxidize to ketones ($\text{R}_2\text{C=O}$). • Tertiary alcohols ($\text{R}_3\text{COH}$) generally do not oxidize under typical conditions. Since the product is an aldehyde (3-methylbutanal), it must have been formed from the oxidation of a primary alcohol. Step 3: Deduce the structure and name of the primary alcohol. To find the corresponding primary alcohol, we replace the aldehyde group ($\text{-CHO}$) with a primary alcohol group ($\text{-CH}_2\text{OH}$). So, the structure of the alcohol is: $$ \text{CH}_3 - \text{CH}(\text{CH}_3) - \text{CH}_2 - \text{CH}_2\text{OH} $$ To name this alcohol: 1. Identify the longest carbon chain containing the hydroxyl group ($\text{-OH}$). This chain has 4 carbons. 2. Number the chain from the end closest to the hydroxyl group. The -OH group is on $\text{C}_1$. 3. Identify substituents: There is a methyl group ($\text{CH}_3$) on $\text{C}_3$. 4. The parent name is butan-1-ol (for a 4-carbon alcohol with -OH on $\text{C}_1$). 5. The full IUPAC name is 3-methylbutan-1-ol. Comparing this with typical multiple-choice options (which were not provided in this turn but are implied by the question format), 3-methylbutan-1-ol is the correct answer. The alcohol that would produce 3-methylbutanal upon oxidation is $\boxed{\text{3-methylbutan-1-ol}}$.