Identify the nature of the acid.

Question

ScanSolve AI Tutor · Accepted Answer

To calculate the pH of a 0.001 M HCl solution:

Identify the nature of the acid.
HCl is a strong acid, which means it dissociates completely in water.
Determine the concentration of hydrogen ions ( $[\text{H}^+]$ ).
Since HCl is a strong acid and dissociates completely:
$\text{HCl} \rightarrow \text{H}^+ + \text{Cl}^-$
The concentration of $\text{H}^+$ ions will be equal to the initial concentration of HCl.
$[\text{H}^+] = 0.001 \text{ M}$
Use the pH formula.
The pH is defined as the negative logarithm (base 10) of the hydrogen ion concentration:
$\text{pH} = -\log_{10}[\text{H}^+]$
Substitute the value and calculate the pH.
$\text{pH} = -\log_{10}(0.001)$ $\text{pH} = -\log_{10}(10^{-3})$ $\text{pH} = -(-3)$ $\text{pH} = 3$
The pH of the 0.001 M HCl solution is $\boxed{\text{3}}$ .

Answer