This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
The reaction shows ethene (H_2C=CH_2) reacting with H-Br. The curved arrow indicates that the pi electrons from the double bond of ethene attack the hydrogen atom of H-Br. Simultaneously, the bond between hydrogen and bromine breaks, with the electrons going to bromine. Let's analyze the role of ethene based on acid-base definitions: Brønsted-Lowry definition: An acid is a proton (H^+) donor. A base is a proton (H^+) acceptor. In this reaction, ethene accepts a proton from H-Br. Therefore, ethene acts as a Brønsted-Lowry base. Lewis definition: An acid is an electron pair acceptor. A base is an electron pair donor. Ethene uses its pi electrons (an electron pair) to form a new bond with the hydrogen atom. Therefore, ethene acts as a Lewis base. Given the options: A. Brønsted-Lowry acid (Incorrect, ethene accepts a proton, it doesn't donate one) B. Brønsted-Lowry base (Correct, ethene accepts a proton) C. Lewis acid (Incorrect, ethene donates an electron pair, it doesn't accept one) D. none of the above Since ethene accepts a proton, it is correctly described as a Brønsted-Lowry base. The final answer is B