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Give the IUPAC names of the following alkanes

Chemistry

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EXERCISES

1. Give the IUPAC names of the following alkanes

  • a) (C₂H₅)₂-CH-CH₃
  1. Expand the condensed formula to CH₃-CH₂-CH(CH₂CH₃)-CH₃.

  2. Identify the longest carbon chain, which is 5 carbons long (pentane).

  3. Number the chain to give the substituent the lowest possible number.

    The ethyl group is at position 3. * Name: 3-ethylpentane

    • b) CH₃-C (CH₃)₂-CH (CH₃)-CH₃
  4. Expand the condensed formula to CH₃-C(CH₃)₂-CH(CH₃)-CH₃.

  5. Identify the longest carbon chain, which is 5 carbons long (pentane).

  6. Number the chain to give the substituents the lowest possible numbers.

    Numbering from the left gives methyl groups at positions 2, 2, and 4. * Name: 2,2,4-trimethylpentane

    • c) C₂H₅-CH (CH₃)-CH₂-CH (CH₃)₂
  7. Expand the condensed formula to CH₃-CH₂-CH(CH₃)-CH₂-CH(CH₃)-CH₃.

  8. Identify the longest carbon chain, which is 6 carbons long (hexane).

  9. Number the chain to give the substituents the lowest possible numbers.

    Numbering from the right gives methyl groups at positions 2 and 4. * Name: 2,4-dimethylhexane

    • d) (CH₃)₂-CH-CH₂-CH₂-CH (CH₃)₂
  10. Expand the condensed formula to CH₃-CH(CH₃)-CH₂-CH₂-CH(CH₃)-CH₃.

  11. Identify the longest carbon chain, which is 6 carbons long (hexane).

  12. Number the chain to give the substituents the lowest possible numbers.

    Numbering from either end gives methyl groups at positions 2 and 5. * Name: 2,5-dimethylhexane

    • e) CH₃-CH₂-CHCI-C(CH₃)₂-CHBrH₂
  13. Assuming CHBrH₂ is a typo and should be CH₂Br for a stable alkane derivative.

    The expanded formula is CH₃-CH₂-CHCl-C(CH₃)₂-CH₂Br.

  14. Identify the longest carbon chain, which is 5 carbons long (pentane).

  15. Number the chain to give the substituents the lowest possible numbers.

    Numbering from the right gives 1-bromo, 2,2-dimethyl, 3-chloro.

  16. Arrange substituents alphabetically

    bromo, chloro, dimethyl. * Name: 1-bromo-3-chloro-2,2-dimethylpentane

    • f)
  17. Identify the parent ring as cyclohexane.

  18. Identify the substituent as an isopropyl group.

    *   Name: **Isopropylcyclohexane**
    
    • g)
  19. Identify the parent ring as cyclohexane.

  20. Identify the substituents as an ethyl group and a methyl group.

  21. Number the ring to give the substituents the lowest possible numbers, prioritizing alphabetically if there's a choice in numbering.

    Ethyl is at position 1, and methyl is at position 2. * Name: 1-ethyl-2-methylcyclohexane

    • h)
  22. Identify the parent ring as cyclohexane.

  23. Identify the substituent as a straight-chain pentyl group (-CH₂(CH₂)₃CH₃).

    *   Name: **Pentylcyclohexane**
    

    2. Write the structural formula of the following

    • a) 2,3-dimethylbutane

      CH3-CH(CH3)-CH(CH3)-CH3\text{CH}_3\text{-CH(CH}_3\text{)-CH(CH}_3\text{)-CH}_3
    • b) 2,2,4-trimethylpentane

      CH3-C(CH3)2-CH2-CH(CH3)-CH3\text{CH}_3\text{-C(CH}_3\text{)}_2\text{-CH}_2\text{-CH(CH}_3\text{)-CH}_3
    • c) 2-chloro-2,3-dimethylpentane

      CH3-CCl(CH3)-CH(CH3)-CH2-CH3\text{CH}_3\text{-CCl(CH}_3\text{)-CH(CH}_3\text{)-CH}_2\text{-CH}_3
    • d) 2,3-dibromo-1-chloro-3-methylhexane

      CH2Cl-CHBr-CBr(CH3)-CH2-CH2-CH3\text{CH}_2\text{Cl-CHBr-CBr(CH}_3\text{)-CH}_2\text{-CH}_2\text{-CH}_3
    • e) 2-chloro-3,3-dimethylbutane

      CH3-CHCl-C(CH3)2-CH3\text{CH}_3\text{-CHCl-C(CH}_3\text{)}_2\text{-CH}_3
    • f) 2-chloro-2,3-dimethylpentane

      CH3-CCl(CH3)-CH(CH3)-CH2-CH3\text{CH}_3\text{-CCl(CH}_3\text{)-CH(CH}_3\text{)-CH}_2\text{-CH}_3

    EXERCISE

    1. Write the IUPAC name of the following compounds:

    • a) (CH₃)₂CHCH=CHCH₂CH₃
  24. Expand the formula to CH₃-CH(CH₃)-CH=CH-CH₂-CH₃.

  25. Identify the longest carbon chain containing the double bond, which is 6 carbons long (hexene).

  26. Number the chain to give the double bond the lowest possible number.

    The double bond is between C3 and C4. The methyl group is at C2. * Name: 2-methylhex-3-ene

    • b)
  27. The structure is CH≡C-CH=CH-CH₂-CH₃.

  28. Identify the longest carbon chain containing both multiple bonds, which is 6 carbons long (hex).

  29. Number the chain to give the multiple bonds the lowest possible numbers.

    Prioritize the double bond if there's a tie. Number

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