Give the IUPAC names of the following alkanes

Here are the solutions to the exercises: EXERCISES 1. Give the IUPAC names of the following alkanes a)* (C₂H₅)₂-CH-CH₃ Step 1: Expand the condensed formula to CH₃-CH₂-CH(CH₂CH₃)-CH₃. Step 2: Identify the longest carbon chain, which is 5 carbons long (pentane). Step 3: Number the chain to give the substituent the lowest possible number. The ethyl group is at position 3. Name: 3-ethylpentane* b)* CH₃-C (CH₃)₂-CH (CH₃)-CH₃ Step 1: Expand the condensed formula to CH₃-C(CH₃)₂-CH(CH₃)-CH₃. Step 2: Identify the longest carbon chain, which is 5 carbons long (pentane). Step 3: Number the chain to give the substituents the lowest possible numbers. Numbering from the left gives methyl groups at positions 2, 2, and 4. Name: 2,2,4-trimethylpentane* c)* C₂H₅-CH (CH₃)-CH₂-CH (CH₃)₂ Step 1: Expand the condensed formula to CH₃-CH₂-CH(CH₃)-CH₂-CH(CH₃)-CH₃. Step 2: Identify the longest carbon chain, which is 6 carbons long (hexane). Step 3: Number the chain to give the substituents the lowest possible numbers. Numbering from the right gives methyl groups at positions 2 and 4. Name: 2,4-dimethylhexane* d)* (CH₃)₂-CH-CH₂-CH₂-CH (CH₃)₂ Step 1: Expand the condensed formula to CH₃-CH(CH₃)-CH₂-CH₂-CH(CH₃)-CH₃. Step 2: Identify the longest carbon chain, which is 6 carbons long (hexane). Step 3: Number the chain to give the substituents the lowest possible numbers. Numbering from either end gives methyl groups at positions 2 and 5. Name: 2,5-dimethylhexane* e)* CH₃-CH₂-CHCI-C(CH₃)₂-CHBrH₂ Step 1: Assuming CHBrH₂ is a typo and should be CH₂Br for a stable alkane derivative. The expanded formula is CH₃-CH₂-CHCl-C(CH₃)₂-CH₂Br. Step 2: Identify the longest carbon chain, which is 5 carbons long (pentane). Step 3: Number the chain to give the substituents the lowest possible numbers. Numbering from the right gives 1-bromo, 2,2-dimethyl, 3-chloro. Step 4: Arrange substituents alphabetically: bromo, chloro, dimethyl. Name: 1-bromo-3-chloro-2,2-dimethylpentane* f)* Step 1: Identify the parent ring as cyclohexane. Step 2: Identify the substituent as an isopropyl group. Name: Isopropylcyclohexane* g)* Step 1: Identify the parent ring as cyclohexane. Step 2: Identify the substituents as an ethyl group and a methyl group. Step 3: Number the ring to give the substituents the lowest possible numbers, prioritizing alphabetically if there's a choice in numbering. Ethyl is at position 1, and methyl is at position 2. Name: 1-ethyl-2-methylcyclohexane* h)* Step 1: Identify the parent ring as cyclohexane. Step 2: Identify the substituent as a straight-chain pentyl group (-CH₂(CH₂)₃CH₃). Name: Pentylcyclohexane* 2. Write the structural formula of the following a)* 2,3-dimethylbutane CH_3-CH(CH_3)-CH(CH_3)-CH_3 b)* 2,2,4-trimethylpentane CH_3-C(CH_3)_2-CH_2-CH(CH_3)-CH_3 c)* 2-chloro-2,3-dimethylpentane CH_3-CCl(CH_3)-CH(CH_3)-CH_2-CH_3 d)* 2,3-dibromo-1-chloro-3-methylhexane CH_2Cl-CHBr-CBr(CH_3)-CH_2-CH_2-CH_3 e)* 2-chloro-3,3-dimethylbutane CH_3-CHCl-C(CH_3)_2-CH_3 f)* 2-chloro-2,3-dimethylpentane CH_3-CCl(CH_3)-CH(CH_3)-CH_2-CH_3 EXERCISE 1. Write the IUPAC name of the following compounds: a)* (CH₃)₂CHCH=CHCH₂CH₃ Step 1: Expand the formula to CH₃-CH(CH₃)-CH=CH-CH₂-CH₃. Step 2: Identify the longest carbon chain containing the double bond, which is 6 carbons long (hexene). Step 3: Number the chain to give the double bond the lowest possible number. The double bond is between C3 and C4. The methyl group is at C2. Name: 2-methylhex-3-ene* b)* Step 1: The structure is CH≡C-CH=CH-CH₂-CH₃. Step 2: Identify the longest carbon chain containing both multiple bonds, which is 6 carbons long (hex). Step 3: Number the chain to give the multiple bonds the lowest possible numbers. Prioritize the double bond if there's a tie. Number