This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Step 1: Calculate the molar mass of ammonia (NH_3). Molar mass of NH_3 = Atomic mass of N + (3 × Atomic mass of H) Molar mass of NH_3 = 14.0 g/mol + (3 × 1.0 g/mol) Molar mass of NH_3 = 14.0 g/mol + 3.0 g/mol = 17.0 g/mol Step 2: Convert the mass of ammonia from kilograms to grams. Mass of NH_3 = 340 kg = 340 × 1000 g = 340000 g Step 3: Calculate the moles of ammonia (NH_3). Moles of NH_3 = Mass of NH_3Molar mass of NH_3 Moles of NH_3 = 340000 g17.0 g/mol Moles of NH_3 = 20000 mol Step 4: Use the stoichiometry of the balanced equation to find the moles of urea formed. The balanced chemical equation is: 2NH_3(g) + CO_2(g) → (NH_2)_2CO(aq) + H_2O(l) From the equation, 2 moles of NH_3 produce 1 mole of urea ((NH_2)_2CO). Since CO_2 is in excess, NH_3 is the limiting reactant. Moles of urea = Moles of NH_3 × 1 mol urea2 mol NH_3 Moles of urea = 20000 mol × (1)/(2) Moles of urea = 10000 mol The moles of urea that were formed are 10000 mol. 3 done, 2 left today. You're making progress.