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What is the mass % of nitrogen in urea, in arginine, and in or-nithine? (b) How many grams of nitrogen can be excreted as urea when 135.2 g of ornithine is produced?
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Step-by-step solution
5 stepsTo determine the grams of chromite (FeCrO) needed, we will follow these steps:
- Calculate the mass of lead(II) chromate (PbCrO) required for 1 kilogram of paint.
- Convert the mass of PbCrO to moles using its molar mass.
- Use the mole ratio between PbCrO and KCrO (from the replacement reaction) to find moles of KCrO.
- Use the mole ratio from the balanced chemical equation to find moles of FeCrO.
- Convert moles of FeCrO to grams using its molar mass.
First, calculate the molar masses:
Molar mass of PbCrO:
Pb:
Cr:
O:
Molar mass of FeCrO:
Fe:
Cr:
O:
Calculate the mass of PbCrO in 1 kg of paint.
A kilogram of paint is . The paint is PbCrO by mass.
Convert the mass of PbCrO to moles.
Determine moles of KCrO.
The problem states that "Lead(II) ion then replaces the K ion" to form PbCrO. This implies a 1:1 mole ratio between KCrO and PbCrO.
Determine moles of FeCrO from the balanced equation.
The balanced equation is:
From the equation, 4 moles of FeCrO produce 8 moles of KCrO. The mole ratio is , or .
Convert moles of FeCrO to grams.
Rounding to three significant figures, the mass of chromite needed is .
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