This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Let's break down the naming of the coordination compound CrCl₂(H₂O)₃NO₃Cl·2H₂O step by step. The compound can be separated into the complex ion, the counter ion, and the water of crystallization: [CrCl₂(H₂O)₃NO₃]⁺ Cl⁻ · 2H₂O Step 1: Identify the central metal atom. The central metal atom is Chromium* (Cr). Step 2: Identify the ligands inside the coordination sphere. There are three types of ligands: H₂O: called aqua* (neutral ligand) Cl⁻: called chloro* (anionic ligand) NO₃⁻: called nitrato* (anionic ligand) Step 3: Determine the number of each ligand and their prefixes. Three H₂O ligands: triaqua* Two Cl⁻ ligands: dichloro* One NO₃⁻ ligand: nitrato* Step 4: Determine the oxidation state of the central metal. Let the oxidation state of Cr be x. The charge of H₂O is 0. The charge of Cl⁻ is -1. The charge of NO₃⁻ is -1. The counter ion outside the coordination sphere is Cl⁻, which has a charge of -1. This means the complex ion [CrCl₂(H₂O)₃NO₃] must have a charge of +1 to balance it. So, for the complex ion: x + 2(-1) + 3(0) + 1(-1) = +1 x - 2 + 0 - 1 = +1 x - 3 = +1 x = +4 Therefore, the oxidation state of Chromium is (IV)*. Step 5: Name the complex ion. Ligands are named in alphabetical order (ignoring prefixes): aqua, chloro, nitrato. Combine the ligand names with their prefixes, followed by the metal name and its oxidation state in Roman numerals. triaquodichloronitratochromium(IV)* Step 6: Name the counter ion. The ion outside the coordination sphere is Cl⁻, which is chloride*. Step 7: Include the water of crystallization. There are two molecules of water outside the coordination sphere, so it's dihydrate*. Step 8: Combine all parts to form the full name. The full name is triaquodichloronitratochromium(IV) chloride dihydrate*. 3 done, 2 left today. You're making progress.