Name this compound with explanation vividly (CrCl2(H2O)3No3)Cl.2H2O

Chemistry

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Let's break down the naming of the coordination compound CrCl₂(H₂O)₃NO₃Cl·2H₂O step by step.

The compound can be separated into the complex ion, the counter ion, and the water of crystallization:
[CrCl₂(H₂O)₃NO₃]⁺ Cl⁻ · 2H₂O

  1. Identify the central metal atom.

    • The central metal atom is Chromium (Cr).
  2. Identify the ligands inside the coordination sphere.

    • There are three types of ligands:
      • H₂O: called aqua (neutral ligand)
      • Cl⁻: called chloro (anionic ligand)
      • NO₃⁻: called nitrato (anionic ligand)
  3. Determine the number of each ligand and their prefixes.

    • Three H₂O ligands: triaqua
    • Two Cl⁻ ligands: dichloro
    • One NO₃⁻ ligand: nitrato
  4. Determine the oxidation state of the central metal.

    • Let the oxidation state of Cr be x.
    • The charge of H₂O is 0.
    • The charge of Cl⁻ is -1.
    • The charge of NO₃⁻ is -1.
    • The counter ion outside the coordination sphere is Cl⁻, which has a charge of -1. This means the complex ion [CrCl₂(H₂O)₃NO₃] must have a charge of +1 to balance it.
    • So, for the complex ion: x + 2(-1) + 3(0) + 1(-1) = +1
    • x - 2 + 0 - 1 = +1
    • x - 3 = +1
    • x = +4
    • Therefore, the oxidation state of Chromium is (IV).
  5. Name the complex ion.

    • Ligands are named in alphabetical order (ignoring prefixes): aqua, chloro, nitrato.
    • Combine the ligand names with their prefixes, followed by the metal name and its oxidation state in Roman numerals.
    • triaquodichloronitratochromium(IV)
  6. Name the counter ion.

    • The ion outside the coordination sphere is Cl⁻, which is chloride.
  7. Include the water of crystallization.

    • There are two molecules of water outside the coordination sphere, so it's dihydrate.
  8. Combine all parts to form the full name.

    • The full name is triaquodichloronitratochromium(IV) chloride dihydrate.
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