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Q13: Which of the following best describes the relationship between pH and H+ ion concentration?

Chemistry

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Q19:

  1. Identify the given values for the initial concentration (M1M_1), initial volume (V1V_1), and final volume (V2V_2).

    The dilution formula is M1V1=M2V2M_1V_1 = M_2V_2.

    M1=2.0 mol/dm3M_1 = 2.0 \text{ mol/dm}^3 V1=50 cm3V_1 = 50 \text{ cm}^3 V2=200 cm3V_2 = 200 \text{ cm}^3
  2. Rearrange the formula to solve for the new concentration (M2M_2) and substitute the values.

    M2=M1V1V2M_2 = \frac{M_1V_1}{V_2} M2=(2.0 mol/dm3)(50 cm3)200 cm3M_2 = \frac{(2.0 \text{ mol/dm}^3)(50 \text{ cm}^3)}{200 \text{ cm}^3}
  3. Calculate the new concentration.

    M2=100 mol/dm3⋅cm3200 cm3M_2 = \frac{100 \text{ mol/dm}^3 \cdot \text{cm}^3}{200 \text{ cm}^3} M2=0.5 mol/dm3M_2 = 0.5 \text{ mol/dm}^3

    The new concentration is B. 0.5 mol/dm³.

    Q20:
    The pH scale is a measure of the acidity or alkalinity of a solution.
    The pH scale ranges from D. 1 to 14. (Note: While 0-14 is common, 1-14 is also considered a valid range in some contexts, especially for general chemistry questions where 0 is extremely acidic and 14 is extremely basic). Given the options, 1 to 14 is the most appropriate choice.

    Q21:

  4. Identify the given values for the initial concentration (M1M_1), final concentration (M2M_2), and final volume (V2V_2).

    The dilution formula is M1V1=M2V2M_1V_1 = M_2V_2.

    M1=0.5 mol/dm3M_1 = 0.5 \text{ mol/dm}^3 M2=0.1 mol/dm3M_2 = 0.1 \text{ mol/dm}^3 V2=500 cm3V_2 = 500 \text{ cm}^3
  5. Rearrange the formula to solve for the original volume (V1V_1) and substitute the values.

    V1=M2V2M1V_1 = \frac{M_2V_2}{M_1} V1=(0.1 mol/dm3)(500 cm3)0.5 mol/dm3V_1 = \frac{(0.1 \text{ mol/dm}^3)(500 \text{ cm}^3)}{0.5 \text{ mol/dm}^3}
  6. Calculate the original volume.

    V1=50 mol/dm3⋅cm30.5 mol/dm3V_1 = \frac{50 \text{ mol/dm}^3 \cdot \text{cm}^3}{0.5 \text{ mol/dm}^3} V1=100 cm3V_1 = 100 \text{ cm}^3

    The original volume was B. 100 cm³.

    Q22:
    To distinguish between a weak acid and a strong acid, an indicator that shows a range of pH values is needed.
    Litmus paper only indicates if a solution is acidic or basic, not the strength.
    Phenolphthalein changes color in a basic range (pH 8.2-10), making it unsuitable for distinguishing between acids.
    Universal indicator paper changes color over a wide pH range, allowing for a more precise estimation of pH and thus distinguishing between strong and weak acids.
    The most suitable indicator is C. Universal indicator paper.

    Q23:

  7. Identify the chemical formula for calcium carbonate, which is CaCO₃.

  8. List the atomic masses of each element

    Ca=40Ca = 40 C=12C = 12 O=16O = 16
  9. Calculate the molar mass by summing the atomic masses of all atoms in the formula.

    Molar mass of CaCO3=(1×Ca)+(1×C)+(3×O)\text{Molar mass of CaCO}_3 = (1 \times \text{Ca}) + (1 \times \text{C}) + (3 \times \text{O}) Molar mass of CaCO3=(1×40)+(1×12)+(3×16)\text{Molar mass of CaCO}_3 = (1 \times 40) + (1 \times 12) + (3 \times 16) Molar mass of CaCO3=40+12+48\text{Molar mass of CaCO}_3 = 40 + 12 + 48 Molar mass of CaCO3=100 g/mol\text{Molar mass of CaCO}_3 = 100 \text{ g/mol}

    The molar mass of calcium carbonate is C. 100 g/mol.

    Q24:
    When a strong acid is diluted by adding water, the concentration of hydrogen ions (H+H^+) decreases.
    A decrease in H+H^+ concentration means the solution becomes less acidic.
    Since pH is inversely related to acidity (lower pH means higher acidity), a decrease in acidity will cause the pH to increase.
    The pH will B. increase (become less acidic).

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