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QUESTION 2 (Start on a new page.) The letters A to F in the table represent SIX substances:

Chemistry

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Answer

2.1 A chemical bond is a strong attractive force that holds atoms together in a molecule or crystal.

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2.2.1
The molecules with only covalent bonds and that are non-polar are H2\text{H}_2, N2\text{N}_2, and CH4\text{CH}_4.
A

2.2.2
A non-polar molecule with polar bonds is CH4\text{CH}_4. The C-H bonds are polar, but the tetrahedral geometry of the molecule results in the bond dipoles cancelling out, making the molecule non-polar overall.
D

2.3.1
The shape of the molecule in substance D (CH4\text{CH}_4) is tetrahedral.

2.3.2
The Lewis structure for the molecule in substance E (HCN\text{HCN}) is:

H−C≡N:\text{H}-\text{C}\equiv\text{N}:

2.4

  1. Identify the electronegativity values for Li and F.

    The electronegativity of Li is approximately 1.0.
    The electronegativity of F is approximately 4.0.

  2. Calculate the electronegativity difference.

    Electronegativity difference=4.0−1.0=3.0\text{Electronegativity difference} = 4.0 - 1.0 = 3.0
  3. Determine the type of bond based on the difference.

    Since the electronegativity difference (3.0) is greater than 1.7, the bond between Li and F is predominantly ionic.

    2.5
    The Lewis structure for substance B (N2\text{N}_2) is:

    :N≡N::\text{N}\equiv\text{N}:

    Nitrogen gas (N2\text{N}_2) is unreactive at room temperature and normal pressures because it contains a very strong triple covalent bond between the two nitrogen atoms. A large amount of energy is required to break this bond, making it difficult for N2\text{N}_2 to react.

    2.6.1
    The ion formed when substance C (NH3\text{NH}_3) reacts with the H+\text{H}^+ ion is the ammonium ion (NH4+\text{NH}_4^+).

    2.6.2
    Two requirements for the formation of dative covalent bonds are:

    • One atom must have a lone pair of electrons to donate.
    • Another atom or ion must have an empty orbital to accept the lone pair of electrons.
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