This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Morning Daniel👻 — let's get this done. a) Relative atomic mass is the average mass of an atom of an element compared to one-twelfth the mass of an atom of carbon-12. It is a dimensionless quantity. b) i) Step 1: Write the unbalanced reaction between X₂CO₃ and HCl. X_2CO_3(s) + HCl(aq) → XCl(aq) + H_2O(l) + CO_2(g) Step 2: Balance the equation. To balance the X atoms, place a coefficient of 2 in front of XCl. X_2CO_3(s) + HCl(aq) → 2XCl(aq) + H_2O(l) + CO_2(g) To balance the H and Cl atoms, place a coefficient of 2 in front of HCl. X_2CO_3(s) + 2HCl(aq) → 2XCl(aq) + H_2O(l) + CO_2(g) ii) Step 1: Convert the volume of hydrochloric acid from cm³ to dm³. Volume of HCl = 23.6 cm^3 × 1 dm^31000 cm^3 = 0.0236 dm^3 Step 2: Calculate the number of moles of hydrochloric acid using its concentration and volume. Moles of HCl = Concentration × Volume Moles of HCl = 0.15 mol/dm^3 × 0.0236 dm^3 Moles of HCl = 0.00354 mol 0.00354 mol iii) Step 1: Use the stoichiometry from the balanced equation to find the moles of X₂CO₃. From the balanced equation: 1 mole of X_2CO_3 reacts with 2 moles of HCl. Moles of X_2CO_3 = Moles of HCl2 Moles of X_2CO_3 = 0.00354 mol2 Moles of X_2CO_3 = 0.00177 mol 0.00177 mol iv) Step 1: Determine the Relative molecular mass (M_r) of X₂CO₃ using its mass and moles. M_r(X_2CO_3) = Mass of X_2CO_3Moles of X_2CO_3 M_r(X_2CO_3) = 0.245 g0.00177 mol M_r(X_2CO_3) ≈ 138.418 g/mol 138.4 g/mol v) Step 1: Use the Relative molecular mass of X₂CO₃ and the known atomic masses of Carbon (C) and Oxygen (O) to find the Relative atomic mass (RAM) of X. Assume RAM(C) = 12.0 g/mol and RAM(O) = 16.0 g/mol. M_r(X_2CO_3) = 2 × RAM(X) + RAM(C) + 3 × RAM(O) 138.418 = 2 × RAM(X) + 12.0 + 3 × 16.0 138.418 = 2 × RAM(X) + 12.0 + 48.0 138.418 = 2 × RAM(X) + 60.0 Step 2: Solve for RAM(X). 2 × RAM(X) = 138.418 - 60.0 2 × RAM(X) = 78.418 RAM(X) = (78.418)/(2) RAM(X) = 39.209 g/mol 39.2 g/mol Send me the next one 📸