Tabulate titration results

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To tabulate the results and calculate the average volume of A used, experimental burette readings are required. Since these readings are not provided in the question, I will outline the structure for the tabulation and explain how to calculate the average volume from hypothetical data.

a)

Tabulate titration results
A table is used to record the initial and final burette readings for each titration, and to calculate the volume of solution A (acetic acid) used in each trial. A common practice is to perform a rough titration first, followed by at least two accurate titrations to obtain concordant results. Let's assume a $25.0 \text{ cm}^3$ portion of solution B (KOH) is used.
$\begin{array}{|c|c|c|c|} \hline \text{Titration Number} & \text{Initial Burette Reading (cm}^3\text{)} & \text{Final Burette Reading (cm}^3\text{)} & \text{Volume of A used (cm}^3\text{)} \\ \hline \text{Rough} & \text{e.g., } 0.00 & \text{e.g., } 25.50 & \text{e.g., } 25.50 \\ \text{1} & \text{e.g., } 0.00 & \text{e.g., } 25.10 & \text{e.g., } 25.10 \\ \text{2} & \text{e.g., } 25.10 & \text{e.g., } 50.15 & \text{e.g., } 25.05 \\ \text{3} & \text{e.g., } 0.00 & \text{e.g., } 25.00 & \text{e.g., } 25.00 \\ \hline \end{array}$
Identify concordant titres
Concordant titres are those that are in close agreement, typically within $\pm 0.10 \text{ cm}^3$ or $\pm 0.05 \text{ cm}^3$ of each other. In the hypothetical example above, titrations 2 and 3 (25.05 $\text{cm}^3$ and 25.00 $\text{cm}^3$ ) are concordant as they are within $0.05 \text{ cm}^3$ .
Calculate the average volume of A used
The average volume is calculated by summing the concordant titre values and dividing by the number of concordant titrations. Using the hypothetical concordant values from Step 2:
$\text{Average volume of A used} = \frac{\text{Volume from Titration 2} + \text{Volume from Titration 3}}{\text{Number of concordant titrations}}$ $\text{Average volume of A used} = \frac{25.05 \text{ cm}^3 + 25.00 \text{ cm}^3}{2}$ $\text{Average volume of A used} = \frac{50.05 \text{ cm}^3}{2}$ $\text{Average volume of A used} = \boxed{\text{25.025 cm}^3}$
Note: Without actual experimental data, a numerical answer for the average volume of A used cannot be definitively provided.

Tabulate titration results

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Tabulate titration results

Identify concordant titres

Calculate the average volume of A used

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