This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Hey Dany, good to see you again. The image shows the chemical structure of a dipeptide. 1. Identification of the Molecule: The molecule shown is NH_2-CH_2-C(=O)-NH-CH_2-COOH. This is a dipeptide formed from two molecules of the amino acid glycine. The name of this dipeptide is Glycylglycine (Gly-Gly). 2. Structure and Functional Groups: It consists of two glycine units linked by a peptide bond* (an amide linkage, -C(=O)-NH-). At one end, it has a free amino group* (NH_2). At the other end, it has a free carboxyl group* (COOH). 3. Ionization States (as hinted by the surrounding text about "charged entities"): Like amino acids, dipeptides are amphoteric, meaning they can act as both acids and bases. Their ionization state depends on the pH of the solution. In strongly acidic conditions (low pH): The free amino group (NH_2) will be protonated to NH_3^+, and the carboxyl group (COOH) will remain un-ionized. The molecule will have a net positive charge. NH_3^+-CH_2-C(=O)-NH-CH_2-COOH At physiological pH (around 7, zwitterionic form): The free amino group (NH_2) is protonated to NH_3^+, and the free carboxyl group (COOH) is deprotonated to COO^-. The molecule exists as a zwitterion*, having both positive and negative charges, resulting in a net charge of zero. NH_3^+-CH_2-C(=O)-NH-CH_2-COO^- In strongly basic conditions (high pH): Both the free amino group (NH_2) and the free carboxyl group (COOH) will be deprotonated. The amino group remains NH_2, and the carboxyl group becomes COO^-. The molecule will have a net negative charge. NH_2-CH_2-C(=O)-NH-CH_2-COO^- The peptide bond itself (-C(=O)-NH-) is generally stable and does not ionize under typical physiological conditions. Summary: The molecule is Glycylglycine, a dipeptide. It contains an amino group, a carboxyl group, and a peptide bond. It can exist in different ionic forms depending on the pH, with the zwitterionic form being prevalent at neutral pH, where the amino group is protonated and the carboxyl group is deprotonated. What's next? 📸