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What are the IUPAC name, molecular formula, and empirical formula for the given chemical structure?

Chemistry

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2 parts
b

C2H6O2\text{C}_2\text{H}_6\text{O}_2

c

CH3O\text{CH}_3\text{O}

Step-by-step solution

6 steps

Here's the breakdown for question 1:

The given structure is:

HH∣∣H−C−C−H∣∣OHOH\begin{matrix} \text{H} & \text{H} \\ | & | \\ \text{H} - \text{C} - \text{C} - \text{H} \\ | & | \\ \text{OH} & \text{OH} \end{matrix}

Part a· 2 steps

IUPAC nomenclature

  1. Identify the longest carbon chain and functional groups.

    The molecule has two carbon atoms in a chain and two hydroxyl (-OH) groups, one on each carbon.

  2. Name the compound based on IUPAC rules.

    The parent alkane is ethane. With two hydroxyl groups, it is a diol. The hydroxyl groups are on carbon 1 and carbon 2.
    The IUPAC name is ethane-1,2-diol.

Part b

C2H6O2\text{C}_2\text{H}_6\text{O}_2

Molecular formula

  1. Count the number of each type of atom in the structure.

    There are 2 carbon (C) atoms, 6 hydrogen (H) atoms (2 on each carbon, plus 1 in each OH group), and 2 oxygen (O) atoms.

  2. Write the molecular formula.

    The molecular formula is C2H6O2\boxed{\text{C}_2\text{H}_6\text{O}_2}.

Part c

CH3O\text{CH}_3\text{O}

Empirical formula

  1. Determine the simplest whole-number ratio of atoms from the molecular formula.

    The molecular formula is C2H6O2\text{C}_2\text{H}_6\text{O}_2. The ratio of C:H:O is 2:6:2.

  2. Divide the subscripts by the greatest common divisor.

    The greatest common divisor for 2, 6, and 2 is 2.
    Dividing by 2 gives a ratio of 1:3:1.
    The empirical formula is CH3O\boxed{\text{CH}_3\text{O}}.

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