This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Eharuner, let's knock this out. Here are the explanations for questions 44, 46, 48, and 49: Question 44: Electronic configuration of an element 13 in the subsidiary energy level is An element with atomic number 13 is Aluminum (Al). The ground state electronic configuration* for Aluminum is 1s²2s²2p⁶3s²3p¹. The term "subsidiary energy level" in this context refers to the principal energy levels. The options provided are full electronic configurations. Option A correctly represents the full ground state electronic configuration for an element with 13 electrons. Answer: A. 1s²2s²2p⁶3s²3p¹ Question 46: The periodic property upon which other properties depend on is Nuclear charge (specifically, effective nuclear charge*) is the fundamental property that determines how strongly the nucleus attracts its electrons. This attraction directly influences the size of the atom (atomic radius), the energy required to remove an electron (ionization energy), the energy change when an electron is added (electron affinity), and the ability of an atom to attract electrons in a chemical bond (electronegativity*). Therefore, nuclear charge is the underlying property that dictates many other periodic trends. Answer: D. Nuclear charge Question 48: BeCl_2 when solidified exists as a/an Beryllium chloride (BeCl_2) is a covalent compound. In the gaseous phase, BeCl_2 exists as discrete linear molecules. However, in the solid state, BeCl_2 forms a polymeric chain structure. Each beryllium atom is tetrahedrally coordinated to four chlorine atoms, and each chlorine atom acts as a bridge between two beryllium atoms. This extended network is characteristic of a giant covalent structure*. Answer: A. Giant structure Question 49: The wavelength in nanometers of ultra-violet light in the Balmer series corresponding to a value of n = 7 is? [Rydberg constant = 1.097 x 10⁷ nm⁻¹] The Balmer series corresponds to electron transitions where the electron falls to the second principal energy level (n₁ = 2). The given initial energy level is n₂ = 7. The Rydberg formula is: 1/λ = R (1/n₁² - 1/n₂²) Note:* The Rydberg constant (R) is typically 1.097 × 10⁷ m⁻¹. If the given value of 1.097 × 10⁷ nm⁻¹ were used directly, the resulting wavelength would be extremely small and not in the UV range. We will assume the intended unit for R is m⁻¹ and convert the final answer to nanometers. Step 1: Substitute the values into the Rydberg formula. 1/λ = (1.097 × 10⁷ m⁻¹) (1/2² - 1/7²) 1/λ = (1.097 × 10⁷ m⁻¹) (1/4 - 1/49) 1/λ = (1.097 × 10⁷ m⁻¹) ((49 - 4) / (4 × 49)) 1/λ = (1.097 × 10⁷ m⁻¹) (45 / 196) Step 2: Calculate the value of 1/λ. 1/λ = (1.097 × 10⁷ × 45) / 196 m⁻¹ 1/λ = 493650000 / 196 m⁻¹ 1/λ = 2518622.449 m⁻¹ Step 3: Calculate λ. λ = 1 / 2518622.449 m⁻¹ λ = 3.9704 × 10⁻⁷ m Step 4: Convert λ to nanometers. λ = 3.9704 × 10⁻⁷ m × (10⁹ nm / 1 m) λ = 397.04 nm Answer: D. 397.0 nm What's next? 📸