This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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The question asks for the hybridization of carbon in ethyne. Step 1: Determine the chemical structure of ethyne. Ethyne, also known as acetylene, has the chemical formula C_2H_2. Its structure is H-C-H. Step 2: Analyze the bonding around each carbon atom. Each carbon atom in ethyne is involved in: One single bond (sigma bond) with a hydrogen atom. One triple bond with the other carbon atom. A triple bond consists of one sigma bond and two pi bonds. Step 3: Count the number of sigma bonds and lone pairs around each carbon atom. For each carbon atom: Number of sigma bonds = 1 (to H) + 1 (to C) = 2 Number of lone pairs = 0 Step 4: Determine the hybridization based on the number of electron domains. The number of electron domains (sigma bonds + lone pairs) around each carbon atom is 2. 2 electron domains correspond to sp* hybridization. 3 electron domains correspond to sp²* hybridization. 4 electron domains correspond to sp³* hybridization. Since each carbon atom in ethyne has 2 electron domains, its hybridization is sp. The final answer is D. That's 2 down. 3 left today — send the next one.