We read your photo as:

The reaction of sulfur with hot concentrated nitric acid produces sulfuric acid, nitrogen dioxide, and water. Write the balanced chemical equation, explain why dilute nitric acid or hydrochloric acid

Chemistry

ScanSolve AI Answer

Step-by-step solution

12 steps

Part a· 2 steps

  1. Identify the reactants in Step 1.

    In Step 1, solid sulfur reacts with hot nitric acid.

    S(s)+HNO3(conc)⟶H2SO4(aq)+NO2(g)+H2O(l)\text{S(s)} + \text{HNO}_3\text{(conc)} \longrightarrow \text{H}_2\text{SO}_4\text{(aq)} + \text{NO}_2\text{(g)} + \text{H}_2\text{O(l)}

  2. State an observable change.

    The reaction produces nitrogen dioxide gas (NO2\text{NO}_2).
    Observation: A reddish-brown gas is produced.

Part b· 3 steps

  1. Consider the nature of the reaction in Step 1.

    Step 1 involves the oxidation of sulfur by nitric acid.

  2. Explain why dilute nitric acid is unsuitable.

    Dilute nitric acid is a weaker oxidizing agent compared to concentrated nitric acid and may not be strong enough to oxidize sulfur effectively.

  3. Explain why hydrochloric acid is unsuitable.

    Hydrochloric acid is a non-oxidizing acid and therefore cannot oxidize sulfur.
    Explanation: Dilute nitric acid is a weaker oxidizing agent and may not react with sulfur. Hydrochloric acid is a non-oxidizing acid and will not react with sulfur.

Part c· 1 step

  1. Write the balanced chemical equation for Step 1.

    Sulfur reacts with hot concentrated nitric acid to produce sulfuric acid, nitrogen dioxide gas, and water.

    S(s)+6HNO3(aq)⟶H2SO4(aq)+6NO2(g)+2H2O(l)\boxed{\text{S(s)} + 6\text{HNO}_3\text{(aq)} \longrightarrow \text{H}_2\text{SO}_4\text{(aq)} + 6\text{NO}_2\text{(g)} + 2\text{H}_2\text{O(l)}}

Part d· 2 steps

  1. Identify the reactants in Step 4.

    In Step 4, copper(II) oxide (CuO\text{CuO}) reacts with hydrochloric acid (HCl\text{HCl}).

  2. Write the balanced chemical equation for Step 4.

    Copper(II) oxide is a basic oxide and reacts with hydrochloric acid to form copper(II) chloride solution and water.

    CuO(s)+2HCl(aq)⟶CuCl2(aq)+H2O(l)\boxed{\text{CuO(s)} + 2\text{HCl(aq)} \longrightarrow \text{CuCl}_2\text{(aq)} + \text{H}_2\text{O(l)}}

Part e· 2 steps

  1. Identify Solution A from the flow chart.

    Solution A is formed when sulfur reacts with hot nitric acid in Step 1.

  2. Name Solution A.

    The product of this reaction is sulfuric acid.
    Name: Sulfuric acid

Part f· 2 steps

  1. Identify gas C.

    Gas C produced in Step 1 is nitrogen dioxide (NO2\text{NO}_2).

  2. State and explain a harmful effect.

    Nitrogen dioxide is a major air pollutant.
    Harmful effect: Nitrogen dioxide contributes to acid rain.
    Explanation: It reacts with water and oxygen in the atmosphere to form nitric acid, which falls as acid rain, damaging buildings, vegetation, and aquatic ecosystems.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question

More Chemistry Questions

QWrite the balanced chemical equation for the reaction between sodium chloride and concentrated…QDescribe how nitric acid and sulfuric acid are manufactured.QWrite the balanced chemical equation for the reaction between zinc metal and dilute sulphuric acid…QWrite an equation for the reaction between concentrated Nitric (V) acid and wood charcoal.QA mixture of concentrated Nitric (V) acid and wood charcoal is heated. What observations are made…
See all Chemistry questions →
Got a syllabus? Photograph it and I'll tell you what's due and what's worth the most.
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp