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To tabulate titration results and calculate the average volume of solution A used. However, the image provided only contains the experimental setup details and chemical information, but no actual bur

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The question asks to tabulate titration results and calculate the average volume of solution A used. However, the image provided only contains the experimental setup details and chemical information, but no actual burette readings (initial and final volumes) from a titration experiment.

Therefore, I will assume a standard pipette volume for solution B and generate a set of plausible, concordant burette readings to demonstrate how the tabulation and calculation would be performed.

Assumptions:

  • Pipette volume for solution B (KOH) = 25.0 cm325.0 \text{ cm}^3
  • Burette readings for solution A (CH₃COOH) are assumed as follows to illustrate the process.

Part a(ii)· 2 steps

Calculation of the average volume of A used

(i) Tabulation of results

Titration NumberInitial Burette Reading (cm3\text{cm}^3)Final Burette Reading (cm3\text{cm}^3)Volume of A used (cm3\text{cm}^3)
Rough0.0024.5024.50
10.0024.1024.10
20.0024.0024.00
30.0024.0524.05

  1. Identify concordant titre values.

    Concordant titre values are those that are within ±0.10 cm3\pm 0.10 \text{ cm}^3 of each other. From the assumed data, the concordant values are 24.10 cm324.10 \text{ cm}^3, 24.00 cm324.00 \text{ cm}^3, and 24.05 cm324.05 \text{ cm}^3.

  2. Calculate the average of the concordant titre values.

    Average volume of A=24.10 cm3+24.00 cm3+24.05 cm33\text{Average volume of A} = \frac{24.10 \text{ cm}^3 + 24.00 \text{ cm}^3 + 24.05 \text{ cm}^3}{3} Average volume of A=72.15 cm33\text{Average volume of A} = \frac{72.15 \text{ cm}^3}{3} Average volume of A=24.05 cm3\text{Average volume of A} = 24.05 \text{ cm}^3

    The average volume of A used is 24.05 cm3\boxed{\text{}24.05 \text{ cm}^3\text{}}

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