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State what would be observed when ethanoic acid reacts with CaCO3. Calculate the volume of oxygen required to burn completely 4 moles of C3H8 at s.t.p.

Chemistry

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1. (i) State what would be observed when ethanoic acid reacts with CaCO3\text{CaCO}_3.
When ethanoic acid (an acid) reacts with calcium carbonate (a carbonate), carbon dioxide gas is produced. The observation for the production of a gas is effervescence or fizzing.

  • Effervescence (or fizzing) would be observed.

1. (ii) Calculate the volume of oxygen required to burn completely 4 moles of C3H8\text{C}_3\text{H}_8 at s.t.p. [H = 1.0, C = 12.0, O = 16.0, 1 mole of gas occupies 22.4 dm322.4 \text{ dm}^3 at s.t.p.]

  1. Write the balanced chemical equation for the complete combustion of propane (C3H8\text{C}_3\text{H}_8).

    C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(l)\text{C}_3\text{H}_8\text{(g)} + 5\text{O}_2\text{(g)} \longrightarrow 3\text{CO}_2\text{(g)} + 4\text{H}_2\text{O(l)}

  2. Determine the mole ratio between propane (C3H8\text{C}_3\text{H}_8) and oxygen (O2\text{O}_2).

    From the balanced equation, 1 mole of C3H8\text{C}_3\text{H}_8 reacts with 5 moles of O2\text{O}_2.

  3. Calculate the moles of oxygen required for 4 moles of C3H8\text{C}_3\text{H}_8.

    Moles of O2=Moles of C3H8×5 mol O21 mol C3H8\text{Moles of O}_2 = \text{Moles of C}_3\text{H}_8 \times \frac{5 \text{ mol O}_2}{1 \text{ mol C}_3\text{H}_8} Moles of O2=4 mol×5=20 mol\text{Moles of O}_2 = 4 \text{ mol} \times 5 = 20 \text{ mol}

  4. Calculate the volume of oxygen at s.t.p.

    Given that 1 mole of gas occupies 22.4 dm322.4 \text{ dm}^3 at s.t.p.

    Volume of O2=Moles of O2×Molar volume at s.t.p.\text{Volume of O}_2 = \text{Moles of O}_2 \times \text{Molar volume at s.t.p.} Volume of O2=20 mol×22.4 dm3/mol\text{Volume of O}_2 = 20 \text{ mol} \times 22.4 \text{ dm}^3/\text{mol} Volume of O2=448 dm3\text{Volume of O}_2 = 448 \text{ dm}^3

    The volume of oxygen required is 448 dm3\boxed{\text{448 dm}^3}.

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