Design full address using two half adder

Computer Engineering

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Answer

To design a full adder using two half adders, we can break down the full adder's logic into components that can be implemented by half adders and an additional OR gate.

Step-by-step solution

3 steps

A full adder takes three inputs (A, B, and Carry-in (Cin\text{C}_{\text{in}})) and produces two outputs (Sum and Carry-out (Cout\text{C}_{\text{out}})).
The Boolean expressions for a full adder are:

  • Sum=A⊕B⊕Cin\text{Sum} = \text{A} \oplus \text{B} \oplus \text{C}_{\text{in}}
  • Cout=(A⋅B)+(Cin⋅(A⊕B))\text{C}_{\text{out}} = (\text{A} \cdot \text{B}) + (\text{C}_{\text{in}} \cdot (\text{A} \oplus \text{B}))

A half adder takes two inputs (A and B) and produces two outputs (Sum and Carry).
The Boolean expressions for a half adder are:

  • Sum=A⊕B\text{Sum} = \text{A} \oplus \text{B}
  • Carry=A⋅B\text{Carry} = \text{A} \cdot \text{B}

Here's how to construct a full adder:

  1. First Half Adder (HA1)

    Connect inputs A and B to the first half adder.

    • The sum output of HA1 will be S1=A⊕B\text{S}_1 = \text{A} \oplus \text{B}.
    • The carry output of HA1 will be C1=A⋅B\text{C}_1 = \text{A} \cdot \text{B}.
  2. Second Half Adder (HA2)

    Connect the sum output of HA1 (S1\text{S}_1) and the Carry-in (Cin\text{C}_{\text{in}}) to the second half adder.

    • The sum output of HA2 will be S2=S1⊕Cin=(A⊕B)⊕Cin\text{S}_2 = \text{S}_1 \oplus \text{C}_{\text{in}} = (\text{A} \oplus \text{B}) \oplus \text{C}_{\text{in}}. This is the final Sum output of the full adder.
    • The carry output of HA2 will be C2=S1⋅Cin=(A⊕B)⋅Cin\text{C}_2 = \text{S}_1 \cdot \text{C}_{\text{in}} = (\text{A} \oplus \text{B}) \cdot \text{C}_{\text{in}}.
  3. OR Gate for Carry-out

    The final Carry-out (Cout\text{C}_{\text{out}}) of the full adder is obtained by ORing the carry outputs from both half adders.

    • Connect C1\text{C}_1 (from HA1) and C2\text{C}_2 (from HA2) to an OR gate.
    • The output of the OR gate will be Cout=C1+C2=(A⋅B)+((A⊕B)⋅Cin)\text{C}_{\text{out}} = \text{C}_1 + \text{C}_2 = (\text{A} \cdot \text{B}) + ((\text{A} \oplus \text{B}) \cdot \text{C}_{\text{in}}). This is the final Carry-out output of the full adder.

    The full adder design using two half adders and one OR gate is:

    • Inputs: A, B, Cin\text{C}_{\text{in}}
    • Outputs: Sum, Cout\text{C}_{\text{out}}

    The final circuit diagram would show:

    1. HA1 with inputs A and B.
    2. HA2 with inputs HA1Sum\text{HA1}_{\text{Sum}} and Cin\text{C}_{\text{in}}.
    3. An OR gate with inputs HA1Carry\text{HA1}_{\text{Carry}} and HA2Carry\text{HA2}_{\text{Carry}}.
    4. The output of HA2's sum is the Full Adder's Sum.
    5. The output of the OR gate is the Full Adder's Cout\text{C}_{\text{out}}.
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