Help me and plot the graph

Points to plot: From the table in part a) of the previous question, you have the following points:

Scale: Use a scale of 2cm to represent 1 unit on both the x-axis and the y-axis. This means:

• For the x-axis: Mark $x=0$, then $x=1$ will be 2cm to the right, $x=2$ will be 4cm to the right, $x=-1$ will be 2cm to the left, and so on.
• For the y-axis: Mark $y=0$, then $y=1$ will be 2cm upwards, $y=2$ will be 4cm upwards, $y=-1$ will be 2cm downwards, and so on.

Plotting the points:

1. Draw your x and y axes.
2. Mark the scale on both axes according to the 2cm = 1 unit instruction.
3. Plot each point from the table:
   • $(-1, -4)$
   • $(0, 0)$ (the origin)
   • $(1, 2)$
   • $(2, 2)$
   • $(3, 0)$
   • $(4, -4)$

Drawing the curve: Since $f(x) = 3x - x^2$ is a quadratic function with a negative coefficient for $x^2$ (i.e., $a = -1$), its graph is a parabola that opens downwards. Connect the plotted points with a smooth, continuous curve. The curve should be symmetrical. Remember that the maximum point (vertex) is at $(1.5, 2.25)$, as calculated in part d). This point should be the highest point on your curve.