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2.4 Calculate Koketso's average speed and determine if they were within the speed limit. 3.2.5 List and count regional roads from a strip map.

Geography

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3.2.4

  1. Calculate the distance travelled by Koketso.

    From the strip map, the distance from Cape Town to Malmesbury is 65 km.
    The distance from Cape Town to Springbok is 549 km.

    Distance=549 km−65 km=484 km\text{Distance} = 549 \text{ km} - 65 \text{ km} = 484 \text{ km}

  2. Convert the travel time to hours.

    Koketso travelled for 4 hours and 30 minutes.

    Time=4 hours+3060 hours=4+0.5=4.5 hours\text{Time} = 4 \text{ hours} + \frac{30}{60} \text{ hours} = 4 + 0.5 = 4.5 \text{ hours}

  3. Calculate Koketso's average speed.

    Using the formula: Speed=DistanceTime\text{Speed} = \frac{\text{Distance}}{\text{Time}}

    Speed=484 km4.5 hours≈107.56 km/hr\text{Speed} = \frac{484 \text{ km}}{4.5 \text{ hours}} \approx 107.56 \text{ km/hr}

  4. Compare the calculated speed with the accepted speed limit.

    The accepted speed limit is 120 km/hr.
    Since 107.56 km/hr<120 km/hr107.56 \text{ km/hr} < 120 \text{ km/hr}, Koketso was within the accepted speed limit.

    Yes, Koketso was within the accepted speed limit.\boxed{\text{Yes, Koketso was within the accepted speed limit.}}

    3.2.5

  5. List all regional roads shown on the strip map.

    The regional roads are: R27, R45, R363, R364, R355, R358, R357, R352, R353, R354, R356, R359, R360, R361, R362, R365, R366, R367, R368, R369, R370, R371.

  6. Count the total number of regional roads.

    There are 22 regional roads.

  7. Identify and count the even-numbered regional roads.

    Even-numbered roads are those ending in an even digit: R364, R358, R352, R354, R356, R360, R362, R366, R368, R370.
    There are 10 even-numbered regional roads.

  8. Calculate the probability.

    Probability=Number of even-numbered roadsTotal number of regional roads=1022\text{Probability} = \frac{\text{Number of even-numbered roads}}{\text{Total number of regional roads}} = \frac{10}{22}

  9. Round the probability to two decimal places.

    Probability=1022≈0.4545...≈0.45\text{Probability} = \frac{10}{22} \approx 0.4545... \approx 0.45

    The probability of choosing an even-numbered road from the regional roads is:

    0.45\boxed{0.45}
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