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Okay, I understand! My apologies for using French. I will switch to English for all explanations from now on.

The 2(−1)2(-1) comes from the formula used to find the x-coordinate of the turning point (vertex) of a quadratic function.

For a quadratic function in the standard form f(x)=ax2+bx+cf(x) = ax^2 + bx + c:
The x-coordinate of the turning point is given by the formula:

x=−b2ax = -\frac{b}{2a}

In the previous question, the function was f(x)=−x2+5x−4f(x) = -x^2 + 5x - 4.
Let's identify the coefficients aa, bb, and cc from this function:

  • aa is the coefficient of x2x^2. Here, a=−1a = -1.
  • bb is the coefficient of xx. Here, b=5b = 5.
  • cc is the constant term. Here, c=−4c = -4.

Now, when we substitute these values into the formula x=−b2ax = -\frac{b}{2a}:

  • We replace bb with 5.
  • We replace aa with −1-1.

So, the expression becomes:

x=−52(−1)x = -\frac{5}{2(-1)}

The 2 is part of the formula itself, and the (−1)(-1) is the value of aa from the function f(x)=−x2+5x−4f(x) = -x^2 + 5x - 4.

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