A man with normal red blood cells is married to a woman who is a sickle cell carrier. With the aid of a genetic diagram, explain the genetic constitution of their children

Here is the genetic diagram explaining the genetic constitution of their children: Let 'A' represent the allele for normal hemoglobin and 'S' represent the allele for sickle cell hemoglobin. Man with normal red blood cells: His genotype is AA (homozygous dominant). Woman who is a sickle cell carrier: Her genotype is AS (heterozygous). Parental Genotypes: Man: AA Woman: AS Gametes: Man: A, A Woman: A, S Punnett Square: |c|c|c| Gametes & A & A \\ A & AA & AA \\ S & AS & AS \\ Genetic Constitution of Children: Genotypes: 50% of the children will have the genotype AA*. 50% of the children will have the genotype AS*. Phenotypes: Children with genotype AA will have normal red blood cells* (not affected by sickle cell disease and not carriers). Children with genotype AS will be sickle cell carriers* (they have normal red blood cells but carry the sickle cell trait and can pass it on to their children). Therefore, there is a 50% chance for each child to have normal red blood cells and a 50% chance for each child to be a sickle cell carrier. Drop the next question.