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Mathematics

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Answer

6 - 2p

Step-by-step solution

3 steps

The image shows a matrix. Since no specific operation is requested, I will find the determinant of the given matrix, which is a common first step when dealing with matrices containing variables.

The given matrix is:

O=(22p13)O = \begin{pmatrix} 2 & 2p \\ 1 & 3 \end{pmatrix}
  1. Recall the formula for the determinant of a 2×22 \times 2 matrix.

    For a matrix (abcd)\begin{pmatrix} a & b \\ c & d \end{pmatrix}, the determinant is ad−bcad - bc.

  2. Substitute the values from the given matrix into the formula.

    Here, a=2a=2, b=2pb=2p, c=1c=1, and d=3d=3.

    det⁡(O)=(2)(3)−(2p)(1)\det(O) = (2)(3) - (2p)(1)
  3. Perform the multiplication and subtraction.

    det⁡(O)=6−2p\det(O) = 6 - 2p

    The determinant of the matrix is 6−2p6 - 2p.

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