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2 Fill in the correct relationship sign ( < , > or = ): 0,72 ______ 0,720

Mathematics

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Step-by-step solution

7 steps
  1. Fill in the correct relationship sign for 0,72 and 0,720 (from question 3.2).

    The number 0,720 is equivalent to 0,72 because trailing zeros after the decimal point do not change the value of the number.

    0,72=0,7200,72 \boxed{=} 0,720
  2. Calculate 84,637−46,25484,637 - 46,254 using the column method (from question 3.3).

    Align the numbers by their decimal points and subtract column by column, starting from the right.

      84.637
    - 46.254
    --------
      38.383
    
    84,637−46,254=38,38384,637 - 46,254 = \boxed{38,383}
  3. Calculate 64,8÷664,8 \div 6 using long division (from question 3.4).

    Divide 64,8 by 6:

    • 6 goes into 6 once (1×6=61 \times 6 = 6).
    • Bring down 4. 6 goes into 4 zero times (0×6=00 \times 6 = 0).
    • Place the decimal point in the quotient.
    • Bring down 8. 6 goes into 48 eight times (8×6=488 \times 6 = 48).
    10.86)64.8‾−6↓04−0↓48−480\begin{array}{r} 10.8 \\ 6\overline{)64.8} \\ -6\downarrow \\ \hline 04 \\ -0\downarrow \\ \hline 48 \\ -48 \\ \hline 0 \end{array} 64,8÷6=10,864,8 \div 6 = \boxed{10,8}
  4. Calculate Thabo's earnings (from question 3.5).

    • 3.5.1 How much does he earn per day? Thabo earns R 47,50 per hour and works 8 hours per day.

      Daily earnings=Hourly rate×Hours per day\text{Daily earnings} = \text{Hourly rate} \times \text{Hours per day} Daily earnings=R 47,50×8=R 380,00\text{Daily earnings} = \text{R }47,50 \times 8 = \text{R }380,00

      Thabo earns R 380,00\boxed{\text{R }380,00} per day.

    • 3.5.2 How much does he earn per week? Thabo works 5 days per week.

      Weekly earnings=Daily earnings×Days per week\text{Weekly earnings} = \text{Daily earnings} \times \text{Days per week} Weekly earnings=R 380,00×5=R 1900,00\text{Weekly earnings} = \text{R }380,00 \times 5 = \text{R }1900,00

      Thabo earns R 1900,00\boxed{\text{R }1900,00} per week.

  5. Calculate the exponents (from question 4.1).

    • 4.1.1 Calculate 434^3.

      43=4×4×4=16×4=644^3 = 4 \times 4 \times 4 = 16 \times 4 = 64 43=644^3 = \boxed{64}
    • 4.1.2 Calculate 1253+49\sqrt[3]{125} + \sqrt{49}. First, find the cube root of 125: 5×5×5=1255 \times 5 \times 5 = 125, so 1253=5\sqrt[3]{125} = 5. Next, find the square root of 49: 7×7=497 \times 7 = 49, so 49=7\sqrt{49} = 7. Now, add the results:

      1253+49=5+7=12\sqrt[3]{125} + \sqrt{49} = 5 + 7 = 12 1253+49=12\sqrt[3]{125} + \sqrt{49} = \boxed{12}
  6. Write in exponential form (from question 4.2).

    The expression is 7×7×7×5×57 \times 7 \times 7 \times 5 \times 5.
    The number 7 is multiplied by itself 3 times, so it can be written as 737^3.
    The number 5 is multiplied by itself 2 times, so it can be written as 525^2.

    7×7×7×5×5=73×527 \times 7 \times 7 \times 5 \times 5 = \boxed{7^3 \times 5^2}
  7. Write the numbers in descending order (from question 5.1.1).

    The given numbers are −5;+6;−3;+9;0;−7-5; +6; -3; +9; 0; -7.
    Descending order means from largest to smallest.
    The largest number is +9+9.
    The next largest is +6+6.
    Then 0.
    Then the negative numbers, from largest (closest to zero) to smallest (furthest from zero): −3-3, then −5-5, then −7-7.

    +9;+6;0;−3;−5;−7\boxed{+9; +6; 0; -3; -5; -7}
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