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4x+7y=39−1 2(x−y)=3x+y−2

Mathematics

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Answer

x=35129,y=−3929x = \frac{351}{29}, y = -\frac{39}{29}

Step-by-step solution

4 steps

Here's how to solve the system of equations:

The given system of equations is:

  1. 4x+7y=394x + 7y = 39
  2. 2(x−y)=3x+7y2(x - y) = 3x + 7y
  1. Simplify the second equation.

    Distribute the 2 on the left side and then rearrange the terms to group xx and yy.

    2x−2y=3x+7y2x - 2y = 3x + 7y

    Subtract 3x3x from both sides:

    2x−3x−2y=7y2x - 3x - 2y = 7y −x−2y=7y-x - 2y = 7y

    Add 2y2y to both sides:

    −x=7y+2y-x = 7y + 2y −x=9y-x = 9y

    Multiply by −1-1 to express xx in terms of yy:

    x=−9yx = -9y
  2. Substitute the expression for xx from Step 1 into the first equation.

    Substitute x=−9yx = -9y into 4x+7y=394x + 7y = 39:

    4(−9y)+7y=394(-9y) + 7y = 39
  3. Solve for yy.

    −36y+7y=39-36y + 7y = 39 −29y=39-29y = 39

    Divide by −29-29:

    y=−3929y = -\frac{39}{29}
  4. Substitute the value of yy back into the simplified equation x=−9yx = -9y to find xx.

    x=−9(−3929)x = -9\left(-\frac{39}{29}\right) x=9×3929x = \frac{9 \times 39}{29} x=35129x = \frac{351}{29}

    The solution to the system of equations is:

    x=35129,y=−3929x = \frac{351}{29}, y = -\frac{39}{29}
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