We read your photo as:

A = (1 2 / 0 1) B = (3 1 / 2 0) find 2A + B. C = (2 −3 / 0 4) and D = (5 −2 / -7 1) Express as a Single matrics D2. F = (3 2 / -4 -6) g = (3 −2 / 2 -1) and H = (7 / 1) find GH. M = (8 −4 / -5 3) and N = (1 / 3) find MN

Mathematics

ScanSolve AI Answer

Step-by-step solution

5 steps

Here are the solutions to your matrix problems:

1) Find 2A+B2A + B
Given A=(1201)A = \begin{pmatrix} 1 & 2 \\ 0 & 1 \end{pmatrix} and B=(3120)B = \begin{pmatrix} 3 & 1 \\ 2 & 0 \end{pmatrix}.

  1. Calculate $2A$.

    2A=2(1201)=(2×12×22×02×1)=(2402)2A = 2 \begin{pmatrix} 1 & 2 \\ 0 & 1 \end{pmatrix} = \begin{pmatrix} 2 \times 1 & 2 \times 2 \\ 2 \times 0 & 2 \times 1 \end{pmatrix} = \begin{pmatrix} 2 & 4 \\ 0 & 2 \end{pmatrix}
  2. Add 2A2A and BB.

    2A+B=(2402)+(3120)=(2+34+10+22+0)=(5522)2A + B = \begin{pmatrix} 2 & 4 \\ 0 & 2 \end{pmatrix} + \begin{pmatrix} 3 & 1 \\ 2 & 0 \end{pmatrix} = \begin{pmatrix} 2+3 & 4+1 \\ 0+2 & 2+0 \end{pmatrix} = \begin{pmatrix} 5 & 5 \\ 2 & 2 \end{pmatrix}

    The result is:

    (5522)\boxed{\begin{pmatrix} 5 & 5 \\ 2 & 2 \end{pmatrix}}

    2) Express D2D^2 as a single matrix
    Given D=(5−2−71)D = \begin{pmatrix} 5 & -2 \\ -7 & 1 \end{pmatrix}.

  3. Calculate D2=D×DD^2 = D \times D.

    D2=(5−2−71)(5−2−71)D^2 = \begin{pmatrix} 5 & -2 \\ -7 & 1 \end{pmatrix} \begin{pmatrix} 5 & -2 \\ -7 & 1 \end{pmatrix} D2=((5)(5)+(−2)(−7)(5)(−2)+(−2)(1)(−7)(5)+(1)(−7)(−7)(−2)+(1)(1))D^2 = \begin{pmatrix} (5)(5) + (-2)(-7) & (5)(-2) + (-2)(1) \\ (-7)(5) + (1)(-7) & (-7)(-2) + (1)(1) \end{pmatrix} D2=(25+14−10−2−35−714+1)D^2 = \begin{pmatrix} 25 + 14 & -10 - 2 \\ -35 - 7 & 14 + 1 \end{pmatrix} D2=(39−12−4215)D^2 = \begin{pmatrix} 39 & -12 \\ -42 & 15 \end{pmatrix}

    The result is:

    (39−12−4215)\boxed{\begin{pmatrix} 39 & -12 \\ -42 & 15 \end{pmatrix}}

    3) Find GHGH
    Given G=(3−22−1)G = \begin{pmatrix} 3 & -2 \\ 2 & -1 \end{pmatrix} and H=(71)H = \begin{pmatrix} 7 \\ 1 \end{pmatrix}.

  4. Multiply matrix GG by matrix HH.

    GH=(3−22−1)(71)GH = \begin{pmatrix} 3 & -2 \\ 2 & -1 \end{pmatrix} \begin{pmatrix} 7 \\ 1 \end{pmatrix} GH=((3)(7)+(−2)(1)(2)(7)+(−1)(1))GH = \begin{pmatrix} (3)(7) + (-2)(1) \\ (2)(7) + (-1)(1) \end{pmatrix} GH=(21−214−1)GH = \begin{pmatrix} 21 - 2 \\ 14 - 1 \end{pmatrix} GH=(1913)GH = \begin{pmatrix} 19 \\ 13 \end{pmatrix}

    The result is:

    (1913)\boxed{\begin{pmatrix} 19 \\ 13 \end{pmatrix}}

    4) Find MNMN
    Given M=(8−4−53)M = \begin{pmatrix} 8 & -4 \\ -5 & 3 \end{pmatrix} and N=(13)N = \begin{pmatrix} 1 \\ 3 \end{pmatrix}.

  5. Multiply matrix MM by matrix NN.

    MN=(8−4−53)(13)MN = \begin{pmatrix} 8 & -4 \\ -5 & 3 \end{pmatrix} \begin{pmatrix} 1 \\ 3 \end{pmatrix} MN=((8)(1)+(−4)(3)(−5)(1)+(3)(3))MN = \begin{pmatrix} (8)(1) + (-4)(3) \\ (-5)(1) + (3)(3) \end{pmatrix} MN=(8−12−5+9)MN = \begin{pmatrix} 8 - 12 \\ -5 + 9 \end{pmatrix} MN=(−44)MN = \begin{pmatrix} -4 \\ 4 \end{pmatrix}

    The result is:

    (−44)\boxed{\begin{pmatrix} -4 \\ 4 \end{pmatrix}}
Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp