A 10 kg child requires a dose of 60 mg/kg/day of a medication, administered twice daily. The available suspension is 250 mg/5 mL. Calculate the dose per administration and the total volume of suspensi

$$\text{Total daily dose} = \text{Dose per kg per day} \times \text{Patient weight}$$ $$\text{Total daily dose} = 60 \text{ mg/kg/day} \times 10 \text{ kg} = 600 \text{ mg/day}$$

Since the medication is taken twice daily (BID), there are 2 administrations per day.

$$\text{Dose per administration} = \frac{\text{Total daily dose}}{\text{Number of administrations per day}}$$ $$\text{Dose per administration} = \frac{600 \text{ mg/day}}{2 \text{ administrations/day}} = 300 \text{ mg/administration}$$

The required dose per administration is $\boxed{\text{300 mg}}$.

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$$\text{Total drug needed} = \text{Total daily dose} \times \text{Duration}$$ $$\text{Total drug needed} = 600 \text{ mg/day} \times 7 \text{ days} = 4200 \text{ mg}$$

$$\text{Total volume of suspension} = \frac{\text{Total drug needed}}{\text{Suspension concentration}}$$ $$\text{Total volume of suspension} = \frac{4200 \text{ mg}}{50 \text{ mg/mL}} = 84 \text{ mL}$$

The total volume of suspension required is $\boxed{\text{84 mL}}$.

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$$\text{Number of tablets} = \frac{\text{Total drug needed}}{\text{Tablet strength}}$$ $$\text{Number of tablets} = \frac{4200 \text{ mg}}{500 \text{ mg/tablet}} = 8.4 \text{ tablets}$$

The number of 500 mg tablets needed to compound the suspension is $\boxed{\text{8.4 tablets}}$.