A parallelogram has one angle measuring 110 degrees. Find the measures of the other three angles.

Sam sold 6 cars, and each car was sold for sh 890 000.

The commission rate is 2% of the total selling price.

The commission Sam earned that month was $\boxed{\text{sh 106 800}}$.

34.
A parallelogram has opposite angles equal and consecutive angles supplementary (add up to $180^\circ$).

Angle $a$ and the angle $110^\circ$ are consecutive interior angles along the bottom side, or $a$ is opposite the $110^\circ$ angle if we consider the top-left angle as $110^\circ$ and bottom-right as $a$.
Looking at the diagram, the angle $110^\circ$ is at the top-left vertex, and angle $a$ is at the bottom-right vertex. In a parallelogram, opposite angles are equal.
Therefore, $a = 110^\circ$.
Reason: Opposite angles in a parallelogram are equal.

Angle $b$ is at the top-right vertex. The angle $70^\circ$ is at the bottom-left vertex. In a parallelogram, opposite angles are equal.
Therefore, $b = 70^\circ$.
Reason: Opposite angles in a parallelogram are equal.

Alternatively, using consecutive angles:
Angle $a$ and the $70^\circ$ angle are consecutive angles.

Angle $b$ and the $110^\circ$ angle are consecutive angles.

The sizes of the angles are:
$a = \boxed{110^\circ}$ because opposite angles in a parallelogram are equal.
$b = \boxed{70^\circ}$ because opposite angles in a parallelogram are equal.

35. (a)
To construct triangle NPQ with PQ = 7 cm, NQ = 9 cm, and angle NPQ = $60^\circ$:

Using a ruler, draw a straight line segment PQ of length 7 cm.

• Place the compass needle at point P and draw an arc that intersects PQ. Let this intersection point be X.
• Without changing the compass width, place the needle at X and draw another arc that intersects the first arc. Let this intersection point be Y.
• Draw a ray from P through Y. This ray forms an angle of $60^\circ$ with PQ.

• Place the compass needle at point Q.
• Open the compass to a radius of 9 cm (the length of NQ).
• Draw an arc that intersects the ray drawn in Step 2. The intersection point is N.

• Draw a straight line segment from N to Q.

Triangle NPQ is now constructed.