We read your photo as:

A rectangular painting is 20 cm wide. Its length is 1 1/4 times its width. What is the perimeter of the painting?

Mathematics

ScanSolve AI Answer

Answer

90 cm\text{90 cm}

Step-by-step solution

3 steps
  1. Identify the given width and the relationship between length and width.

    The width of the rectangular painting is given as 20 centimetres.
    The length is 1141\frac{1}{4} times its width.

  2. Calculate the length of the painting.

    First, convert the mixed fraction to an improper fraction:

    114=(1×4)+14=541\frac{1}{4} = \frac{(1 \times 4) + 1}{4} = \frac{5}{4}

    Now, calculate the length:

    Length=54×Width\text{Length} = \frac{5}{4} \times \text{Width} Length=54×20 cm\text{Length} = \frac{5}{4} \times 20 \text{ cm} Length=5×5 cm\text{Length} = 5 \times 5 \text{ cm} Length=25 cm\text{Length} = 25 \text{ cm}
  3. Calculate the perimeter of the painting.

    The formula for the perimeter of a rectangle is P=2×(Length+Width)P = 2 \times (\text{Length} + \text{Width}).
    Substitute the calculated length and given width:

    P=2×(25 cm+20 cm)P = 2 \times (25 \text{ cm} + 20 \text{ cm}) P=2×(45 cm)P = 2 \times (45 \text{ cm}) P=90 cmP = 90 \text{ cm}

    The perimeter of the picture is 90 cm\text{90 cm}.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp