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A student is given a flow diagram with inputs and outputs. The rule is to multiply the input by 9 and add 8. Fill in the missing values, identify the input and output values, state the rule, write num

Mathematics

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Here are the solutions based on the provided flow diagram and questions:

a.i. Complete the flow diagram:

The rule is "×9+8\times 9 + 8".

  • For input 3: 3×9+8=27+8=353 \times 9 + 8 = 27 + 8 = 35
  • For output 89: Let input be xx. x×9+8=89  ⟹  9x=81  ⟹  x=9x \times 9 + 8 = 89 \implies 9x = 81 \implies x = 9
  • For input 4: 4×9+8=36+8=444 \times 9 + 8 = 36 + 8 = 44
  • For input 6: 6×9+8=54+8=626 \times 9 + 8 = 54 + 8 = 62
  • For input 7: 7×9+8=63+8=717 \times 9 + 8 = 63 + 8 = 71
  • For output 17: Let input be yy. y×9+8=17  ⟹  9y=9  ⟹  y=1y \times 9 + 8 = 17 \implies 9y = 9 \implies y = 1

The completed flow diagram values are:

  • Inputs: 3,9,4,6,7,13, 9, 4, 6, 7, 1
  • Outputs: 35,89,44,62,71,1735, 89, 44, 62, 71, 17

a.ii. What are the input values?
The input values are 3, 9, 4, 6, 7, 1\boxed{\text{3, 9, 4, 6, 7, 1}}.

a.iii. What are the output values?
The output values are 35, 89, 44, 62, 71, 17\boxed{\text{35, 89, 44, 62, 71, 17}}.

a.iv. What is the rule?
The rule is multiply by 9 and add 8 (or ×9+8)\boxed{\text{multiply by 9 and add 8 (or } \times 9 + 8)}.

a.v. Number sentences:

  • 3×9+8=353 \times 9 + 8 = 35
  • 9×9+8=899 \times 9 + 8 = 89
  • 4×9+8=444 \times 9 + 8 = 44
  • 6×9+8=626 \times 9 + 8 = 62
  • 7×9+8=717 \times 9 + 8 = 71
  • 1×9+8=171 \times 9 + 8 = 17

a.vi. What will the output values be if the rule is + 2 x 7?
Assuming the rule means (input + 2) ×\times 7, and using the input values from the flow diagram (3, 9, 4, 6, 7, 1):

  • For input 3: (3+2)×7=5×7=35(3 + 2) \times 7 = 5 \times 7 = 35
  • For input 9: (9+2)×7=11×7=77(9 + 2) \times 7 = 11 \times 7 = 77
  • For input 4: (4+2)×7=6×7=42(4 + 2) \times 7 = 6 \times 7 = 42
  • For input 6: (6+2)×7=8×7=56(6 + 2) \times 7 = 8 \times 7 = 56
  • For input 7: (7+2)×7=9×7=63(7 + 2) \times 7 = 9 \times 7 = 63
  • For input 1: (1+2)×7=3×7=21(1 + 2) \times 7 = 3 \times 7 = 21

The output values would be 35, 77, 42, 56, 63, 21\boxed{\text{35, 77, 42, 56, 63, 21}}.

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