A) Two functions h and g are defined by h:x (x)/(x2-1), x +/- 1 and g:x (x)/(x+3), x -3.

Here's the solution to question 9:

a) Two functions $h$ and $g$ are defined by $h:x \to \frac{x}{x^2-1}, x \ne \pm 1$ and $g:x \to \frac{x}{x+3}, x \ne -3$.

i) Find $g^{-1}(-3)$

Step 1: Find the inverse function $g^{-1}(y)$.
Let $y = g(x)$.

$$y = \frac{x}{x+3}$$

Multiply both sides by $(x+3)$:

$$y(x+3) = x$$ $$yx + 3y = x$$

Rearrange to solve