Answer all questions appropriately. 1) Solve the equation. 2) If the bearing of town A from town B is 230 degrees, what is the bearing of town B from town A? 3) Write the vector represented in the diagram.

Here's the solution to the first question. The other questions are not clear enough to read. Step 1: Simplify the numerator by combining the constant terms. (2t+9−6)/(3) = (2t+3)/(3) Step 2: Separate the terms in the numerator. (2t+3)/(3) = 2t/3 + 3/3 Step 3: Simplify the second term. 2t/3 + 1 The simplified expression is 2t/3 + 1.

Answer all questions appropriately. 1) Solve the equation. 2) If the bearing of town A from town B is 230 degrees, what is the bearing of town B from town A? 3) Write the vector represented in the diagram.

Here's the solution to the first question. The other questions are not clear enough to read. Step 1: Simplify the numerator by combining the constant terms. (2t+9−6)/(3) = (2t+3)/(3) Step 2: Separate the terms in the numerator. (2t+3)/(3) = 2t/3 + 3/3 Step 3: Simplify the second term. 2t/3 + 1 The simplified expression is 2t/3 + 1.

Solved: Answer all questions appropriately. 1) Solve the…

Here's the solution to the first question. The other questions are not clear enough to read.

Simplify the numerator by combining the constant terms.
$\frac{2t+9-6}{3} = \frac{2t+3}{3}$
Separate the terms in the numerator.
$\frac{2t+3}{3} = \frac{2t}{3} + \frac{3}{3}$
Simplify the second term.
$\frac{2t}{3} + 1$
The simplified expression is $\boxed{\frac{2t}{3} + 1}$ .

Answer all questions appropriately. 1) Solve the equation. 2) If the bearing of town A from town B is 230 degrees, what is the bearing of town B from town A? 3) Write the vector represented in the diagram.

Step-by-step solution

Simplify the numerator by combining the constant terms.

Separate the terms in the numerator.

Simplify the second term.

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