The equation of the axis of symmetry of a parabola is ______. What is the vertex or turning point of the graph? What is the axis of symmetry of the graph? What is the equation of the parabola?

Step 1: Answer Question 7. For a parabola in the form $y = ax^2 + bx + c$, the equation of the axis of symmetry is given by: $x = -\frac{b}{2a}$ The equation of the axis of symmetry of a parabola is \boxed{x = -\frac{b{2a}}}.

Step 2: Answer Question 8. The graph shows the parabola $y = 2x^2$. The vertex or turning point of a parabola in the form $y = ax^2$ is at the origin $(0,0)$. This is also visible as the lowest point on the graph. The vertex or turning point of the graph is $\boxed{(0,0)}$.

Step 3: Answer Question 9. The axis of symmetry for the parabola $y = 2x^2$ is the vertical line that passes through its vertex $(0,0)$. This line is the y-axis. The equation of the y-axis is $x=0$. Using the formula $x = -\frac{b}{2a}$ for $y = 2x^2$ (where $a=2$, $b=0$, $c=0$): $x = -\frac{0}{2(2)} = 0$ The axis of symmetry of the graph is $\boxed{x=0}$.

Step 4: Answer Question 10. The equation of the parabola is explicitly stated below the graph. The equation of the parabola is $\boxed{y = 2x^2}$.