The equation of the axis of symmetry of a parabola is . What is the vertex or turning point of the graph? What is the axis of symmetry of the graph? What is the equation of the parabola?

For a parabola in the form $y = ax^2 + bx + c$, the equation of the axis of symmetry is given by:

The equation of the axis of symmetry of a parabola is $\boxed{\mathbf{x = -\frac{b}{2a}}}$.

The graph shows the parabola $y = 2x^2$. The vertex or turning point of a parabola in the form $y = ax^2$ is at the origin $(0,0)$. This is also visible as the lowest point on the graph.
The vertex or turning point of the graph is $\boxed{\mathbf{(0,0)}}$.

The axis of symmetry for the parabola $y = 2x^2$ is the vertical line that passes through its vertex $(0,0)$. This line is the y-axis.
The equation of the y-axis is $x=0$.
Using the formula $x = -\frac{b}{2a}$ for $y = 2x^2$ (where $a=2$, $b=0$, $c=0$):

The axis of symmetry of the graph is $\boxed{\mathbf{x=0}}$.

The equation of the parabola is explicitly stated below the graph.
The equation of the parabola is $\boxed{\mathbf{y = 2x^2}}$.