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Answer the following questions in mathematics: What type of function is f(x) = x2 + 5x + 6? State the Remainder Theorem. What are the conditions for a function to be continuous at a point? What is a s

Mathematics

ScanSolve AI Answer

Graph of f(x) = x² + 5x + 6

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Key points of f(x) = x² + 5x + 6
Pointxy
x-intercept−30
Minimum−2.5−0.25
x-intercept−20
y-intercept06

Step-by-step solution

10 steps
  1. Answer Question 1.

    The function f(x)=x2+5x+6f(x) = x^2 + 5x + 6 is a polynomial function of degree 2.

    • Quadratic function
  2. Answer Question 2.

    The Remainder Theorem states that if a polynomial P(x)P(x) is divided by a linear divisor (x−a)(x-a), then the remainder is P(a)P(a).

  3. Answer Question 3.

    A function f(x)f(x) is continuous at the point x=ax=a if and only if:

    • f(a)f(a) is defined.
    • lim⁡x→af(x)\lim_{x \to a} f(x) exists.
    • lim⁡x→af(x)=f(a)\lim_{x \to a} f(x) = f(a).
  4. Answer Question 4.

    A singular matrix is a square matrix whose determinant is zero.

    • The determinant value of a singular matrix is 0.
  5. Answer Question 5.

    Two lines with slopes m1m_1 and m2m_2 are parallel if and only if their slopes are equal.

    • m1=m2m_1 = m_2
  6. Answer Question 6.

    A circle is formed when a plane intersects a cone perpendicular to the cone's axis.

  7. Answer Question 7.

    The formula for cos⁡2θ\cos 2\theta in terms of tan⁡θ\tan \theta is:

    cos⁡2θ=1−tan⁡2θ1+tan⁡2θ\cos 2\theta = \frac{1 - \tan^2 \theta}{1 + \tan^2 \theta}
  8. Answer Question 8.

    Given cos⁡A=1\cos A = 1. For an acute angle AA:

    A=cos⁡−1(1)A = \cos^{-1}(1) A=0∘A = 0^\circ
    • 0∘0^\circ
  9. Answer Question 9.

    If β\beta is the angle between two vectors p⃗\vec{p} and q⃗\vec{q}, the formula for cos⁡β\cos \beta is:

    cos⁡β=p⃗⋅q⃗∣p⃗∣∣q⃗∣\cos \beta = \frac{\vec{p} \cdot \vec{q}}{|\vec{p}| |\vec{q}|}
  10. Answer Question 10.

    For inversion, the relation between OPOP, OP′OP', and the radius rr is:

    OP⋅OP′=r2OP \cdot OP' = r^2
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