Determine the area of the entire canvas in square centimetres.

The width is given as $2,46 \text{ ft}$.
We are given the conversion factor $1 \text{ ft} = 30,5 \text{ cm}$.

The length of the canvas is $110 \text{ cm}$.
The formula for the area of a rectangle is $\text{Area} = \text{length} \times \text{width}$.

The area of the entire canvas is $\boxed{8253,3 \text{ cm}^2}$.

4.1.2

The question states that Nandipha "will paint the rest of the canvas" but then asks to "Calculate the total surface area that needs to be painted if she paints the overlap as well." Painting the "overlap as well" means that she applies paint to the entire canvas surface, including the areas that will later be covered by bottlecaps and plastic. Therefore, the total surface area to be painted is the entire area of the canvas.

From question 4.1.1, the area of the entire canvas is $8253,3 \text{ cm}^2$.
The total surface area that needs to be painted is $\boxed{8253,3 \text{ cm}^2}$.

4.1.3

There are three circles. Let's denote them as C1 (largest), C2 (middle), and C3 (smallest).
The largest circle (C1) takes 68 bottlecaps.
The problem states that "each circle is half the size of the adjacent circle." Assuming "size" refers to the area covered by bottlecaps:
Number of caps for C2 = $0,5 \times \text{Number of caps for C1}$

Number of caps for C3 = $0,5 \times \text{Number of caps for C2}$

Add the number of caps for all three circles.

The approximate amount of bottle caps Nandipha will need is $\boxed{119}$.