This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Step 1: Convert the width of the canvas from feet to centimetres. The width is given as . We are given the conversion factor .
Step 2: Calculate the area of the canvas. The length of the canvas is . The formula for the area of a rectangle is . The area of the entire canvas is .
Step 1: Interpret the question regarding the painted area. The question states that Nandipha "will paint the rest of the canvas" but then asks to "Calculate the total surface area that needs to be painted if she paints the overlap as well." Painting the "overlap as well" means that she applies paint to the entire canvas surface, including the areas that will later be covered by bottlecaps and plastic. Therefore, the total surface area to be painted is the entire area of the canvas.
Step 2: State the total surface area to be painted. From question 4.1.1, the area of the entire canvas is . The total surface area that needs to be painted is .
Step 1: Determine the number of bottlecaps for each circle. There are three circles. Let's denote them as C1 (largest), C2 (middle), and C3 (smallest). The largest circle (C1) takes 68 bottlecaps. The problem states that "each circle is half the size of the adjacent circle." Assuming "size" refers to the area covered by bottlecaps: Number of caps for C2 = Number of caps for C3 =
Step 2: Calculate the total number of bottlecaps needed. Add the number of caps for all three circles. The approximate amount of bottle caps Nandipha will need is .
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4.1.1 Step 1: Convert the width of the canvas from feet to centimetres. The width is given as 2,46 ft.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.