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यदि 10⁹ इलेक्ट्रॉन प्रत्येक सेकण्ड में, एक पिण्ड से दूसरे पिण्ड पर स्थानान्तरित होते हैं, तो दूसरे पिण्ड पर 1 C कुल आवेश प्राप्त करने के लिए आवश्यक समय होगा-

Physics

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Answer

(c) 198 वर्ष\textbf{(c) 198 वर्ष}

Step-by-step solution

5 steps
  1. Charge of one electron

    e=1.6×10−19 Ce = 1.6 \times 10^{-19} \, \mathrm{C}

  2. Rate of electrons transferred

    n=109 electrons/secondn = 10^{9} \, \mathrm{electrons/second}

  3. Current produced

    I=n×eI = n \times e I=109×1.6×10−19 C/sI = 10^{9} \times 1.6 \times 10^{-19} \, \mathrm{C/s} I=1.6×109−19=1.6×10−10 AI = 1.6 \times 10^{9-19} = 1.6 \times 10^{-10} \, \mathrm{A}
  4. Time required for 1 C1 \, \mathrm{C} charge

    Total charge Q=1 CQ = 1 \, \mathrm{C}

    t=QIt = \frac{Q}{I} t=11.6×10−10 st = \frac{1}{1.6 \times 10^{-10}} \, \mathrm{s} t=10101.6=6.25×109 st = \frac{10^{10}}{1.6} = 6.25 \times 10^{9} \, \mathrm{s}
  5. Convert seconds to years

    1 year=365 days/year×24 h/day×3600 s/h=3.156×107 s/year1 \, \mathrm{year} = 365 \, \mathrm{days/year} \times 24 \, \mathrm{h/day} \times 3600 \, \mathrm{s/h} = 3.156 \times 10^{7} \, \mathrm{s/year}

    tyears=6.25×1093.156×107t_\mathrm{years} = \frac{6.25 \times 10^{9}}{3.156 \times 10^{7}} tyears=6.253.156×102≈1.98×102=198 yearst_\mathrm{years} = \frac{6.25}{3.156} \times 10^{2} \approx 1.98 \times 10^{2} = 198 \, \mathrm{years}

    (c) 198 वर्ष

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