यदि 109 इलेक्ट्रॉन प्रत्येक सेकण्ड में, एक पिण्ड से दूसरे पिण्ड पर स्थानान्तरित होते हैं, तो दूसरे पिण्ड पर 1 C कुल आवेश प्राप्त करने के लिए आवश्यक समय होगा-

March 22, 2026Physics

ScanSolve AI Answer

March 22, 2026

Answer

Step 1: Charge of one electron
$e = 1.6 \times 10^{-19} \, \mathrm{C}$

Step 2: Rate of electrons transferred
$n = 10^{9} \, \mathrm{electrons/second}$

Step 3: Current produced

I = n \times e

I = 10^{9} \times 1.6 \times 10^{-19} \, C/s

I = 1.6 \times 10^{9-19} = 1.6 \times 10^{-10} \, A

Step 4: Time required for $1 \, \mathrm{C}$ charge
Total charge $Q = 1 \, \mathrm{C}$

t = \frac{Q}{I}

t = \frac{1}{1.6 \times 10^{-10}} \, s

t = \frac{10^{10}}{1.6} = 6.25 \times 10^{9} \, s

Step 5: Convert seconds to years
$1 \, year = 365 \, days/year \times 24 \, h/day \times 3600 \, s/h = 3.156 \times 10^{7} \, \mathrm{s/year}$

t_years = \frac{6.25 \times 10^{9}}{3.156 \times 10^{7}}

t_years = \frac{6.25}{3.156} \times 10^{2} \approx 1.98 \times 10^{2} = 198 \, years

\textbf{(c) 198 वर्ष}

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Charge of one electron e = 1.6 × 10^-19 \, C Step 2: Rate of electrons transferred n = 10^9 \, electrons/second Step 3: Current produced I = n × e I = 10^9 × 1.6 × 10^-19 \, C/s I = 1.6 × 10^9-19 = 1.6 × 10^-10 \, A Step 4: Time required for 1 \, C ch…

Asked on March 22, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on March 22, 2026

Step 1: Charge of one electron e = 1.6 × 10^-19 \, C Step 2: Rate of electrons transferred n = 10^9 \, electrons/second Step 3: Current produced I = n × e I = 10^9 × 1.6 × 10^-19 \, C/s I = 1.6 × 10^9-19 = 1.6 × 10^-10 \, A Step 4: Time required for 1 \, C charge Total charge Q = 1 \, C t = (Q)/(I) t = (1)/(1.6 × 10^-10) \, s t = 10^101.6 = 6.25 × 10^9 \, s Step 5: Convert seconds to years 1 \, year = 365 \, days/year × 24 \, h/day × 3600 \, s/h = 3.156 × 10^7 \, s/year t_years = 6.25 × 10^93.156 × 10^7 t_years = (6.25)/(3.156) × 10^2 ≈ 1.98 × 10^2 = 198 \, years (c) 198 वर्ष