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y=x3+sinx
Step 1: Differentiate each term using the power rule and the derivative of sinx.
dxdy=dxd(x3)+dxd(sinx)
dxdy=3x3−1+cosx
dxdy=3x2+cosx
The derivative is 3x2+cosx.
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y=x2cosx
Step 1: Apply the product rule, dxd(uv)=u′v+uv′, where u=x2 and v=cosx.
Step 2: Find the derivatives of u and v.
u′=dxd(x2)=2x
v′=dxd(cosx)=−sinx
Step 3: Substitute u,v,u′,v′ into the product rule formula.
dxdy=(2x)(cosx)+(x2)(−sinx)
dxdy=2xcosx−x2sinx
The derivative is 2xcosx−x2sinx.
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y=xx2+sinx
Step 1: Apply the quotient rule, dxd(vu)=v2u′v−uv′, where u=x2+sinx and v=x.
Step 2: Find the derivatives of u and v.
u′=dxd(x2+sinx)=2x+cosx
v′=dxd(x)=1
Step 3: Substitute u,v,u′,v′ into the quotient rule formula.
dxdy=x2(2x+cosx)(x)−(x2+sinx)(1)
Step 4: Simplify the expression.
dxdy=x22x2+xcosx−x2−sinx
dxdy=x2x2+xcosx−sinx
The derivative is x2x2+xcosx−sinx.
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y=(x2+1)(sinx)
Step 1: Apply the product rule, dxd(uv)=u′v+uv′, where u=x2+1 and v=sinx.
Step 2: Find the derivatives of u and v.
u′=dxd(x2+1)=2x
v′=dxd(sinx)=cosx
Step 3: Substitute u,v,u′,v′ into the product rule formula.
dxdy=(2x)(sinx)+(x2+1)(cosx)
dxdy=2xsinx+(x2+1)cosx
The derivative is 2xsinx+(x2+1)cosx.
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y=x3tanx
Step 1: Apply the product rule, dxd(uv)=u′v+uv′, where u=x3 and v=tanx.
Step 2: Find the derivatives of u and v.
u′=dxd(x3)=3x2
v′=dxd(tanx)=sec2x
Step 3: Substitute u,v,u′,v′ into the product rule formula.
dxdy=(3x2)(tanx)+(x3)(sec2x)
dxdy=3x2tanx+x3sec2x
The derivative is 3x2tanx+x3sec2x.
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y=x2cosx
Step 1: Apply the quotient rule, dxd(vu)=v2u′v−uv′, where u=cosx and v=x2.
Step 2: Find the derivatives of u and v.
u′=dxd(cosx)=−sinx
v′=dxd(x2)=2x
Step 3: Substitute u,v,u′,v′ into the quotient rule formula.
dxdy=(x2)2(−sinx)(x2)−(cosx)(2x)
Step 4: Simplify the expression.
dxdy=x4−x2sinx−2xcosx
dxdy=x4−x(xsinx+2cosx)
dxdy=x3−(xsinx+2cosx)
The derivative is x3−(xsinx+2cosx).
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y=xsinx+x2
Step 1: Differentiate each term. For xsinx, apply the product rule.
For u=x and v=sinx:
u′=1
v′=cosx
dxd(xsinx)=(1)(sinx)+(x)(cosx)=sinx+xcosx
Step 2: Differentiate x2.
dxd(x2)=2x
Step 3: Combine the derivatives.
dxdy=(sinx+xcosx)+2x
dxdy=sinx+xcosx+2x
The derivative is sinx+xcosx+2x.
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y=(x2+x)cosx
Step 1: Apply the product rule, dxd(uv)=u′v+uv′, where u=x2+x and v=cosx.
Step 2: Find the derivatives of u and v.
u′=dxd(x2+x)=2x+1
v′=dxd(cosx)=−sinx
Step 3: Substitute u,v,u′,v′ into the product rule formula.
dxdy=(2x+1)(cosx)+(x2+x)(−sinx)
dxdy=(2x+1)cosx−(x2+x)sinx
The derivative is (2x+1)cosx−(x2+x)sinx.
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y=sinxx3
Step 1: Apply the quotient rule,