Discuss the difference between truncation and rounding errors, and provide an example of each.

Mathematics

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Truncation error occurs when an infinite process or a continuous function is approximated by a finite one, while rounding error occurs when a number is approximated by a value with fewer significant digits.

Truncation Error:

  • Definition: This error results from stopping an infinite mathematical process (like an infinite series or an integral) after a finite number of steps, or from approximating a continuous function with a discrete one. It's an error due to the method or model used.
  • Example: Approximating the value of exe^x using only the first few terms of its Taylor series expansion. The Taylor series for exe^x is 1+x+x22!+x33!+…1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \dots If we approximate e1e^1 using only the first three terms: e1≈1+1+122!=1+1+0.5=2.5e^1 \approx 1 + 1 + \frac{1^2}{2!} = 1 + 1 + 0.5 = 2.5 The true value of e1e^1 is approximately 2.71828. The truncation error is 2.71828−2.5=0.218282.71828 - 2.5 = 0.21828. This error arises because we "truncated" the infinite series.

Rounding Error:

  • Definition: This error occurs when a number with more significant digits is represented by a number with fewer significant digits, typically due to limitations in storage or display. It's an error due to the representation of a number.
  • Example: Representing the fraction 13\frac{1}{3} as a decimal with a limited number of digits. The true value of 13\frac{1}{3} is 0.333333…0.333333\dots (an infinitely repeating decimal). If we round 13\frac{1}{3} to two decimal places, we get 0.33. The rounding error is 13−0.33=0.333333⋯−0.33=0.003333…\frac{1}{3} - 0.33 = 0.333333\dots - 0.33 = 0.003333\dots
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